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Juliette [100K]

3 years ago

12

When red-headed woodpeckers (melanerpes erythrocephalus) strike the trunk of a tree, they can experience an acceleration ten tim

es greater than the acceleration of gravity, or about 98.1 m/s2. what is this acceleration in in/s2?\?

1 answer:

kifflom [539]3 years ago

8 0

98.1 m/s² × (1 in)/(0.0254 m) ≈ 3862 in/s²

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How high can a 40 N force move a load, when 395 J of work is done?

Juliette [100K]

Answer:

9.875

Explanation:

w=f×s

395=40×s

make s the subject of the formula

s=395/40

=9.875

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3 years ago

Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?

bagirrra123 [75]

Reduce friction because friction just makes things harder

5 0

3 years ago

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when the cross product of vector A and B are 2i+3j+4k and the sum of vector A and B are 3i+8j+7k then what will be the two vecto

Kryger [21]

Explanation:

the two vectors are 5i+11j+11k

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2 years ago

What is the Primacy Effect? Question 1 options:

Vika [28.1K]

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4 years ago

A simple pendulum has a period of 2.5 s. What is its period if its length is increased by a factor of four?

Svetach [21]

Answer:

Its period if its length is increased by a factor of four is 5 s.

Explanation:

The period of a simple pendulum is given by;

$T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi} = \sqrt{\frac{l}{g} } \\\\ \frac{T^2}{4\pi^2} = \frac{l}{g}\\\\\frac{T^2}{l} = \frac{4\pi^2}{g} \\\\let \ \frac{4\pi^2}{g} \ be \ constant \\\\\frac{T_1^2}{l_1} = \frac{T_2^2}{l_2} \\\\$

Given;

initial period, T₁ = 2.5

initial length, = L₁

new length, L₂ = 4L₁

the new period, T₂ = ?

$\frac{T_1^2}{l_1} = \frac{T_2^2}{l_2} \\\\T_2^2 = \frac{T_1^2 l_2}{l_1} \\\\T_2 = \sqrt{\frac{T_1^2 l_2}{l_1}} \\\\ T_2 = \sqrt{\frac{(2.5)^2 \ \times \ 4l_1}{l_1}}\\\\ T_2 =\sqrt{(2.5)^2 \ \times \ 4}\\\\T_2 = \sqrt{25} \\\\T_2 = 5\ s$

Therefore, its period if its length is increased by a factor of four is 5 s.

5 0

3 years ago