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Alisiya [41]
3 years ago
8

20 points and brainliest‼️‼️‼️‼️

Physics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

0 N

Explanation:

Applying,

F = qvBsin∅................. Equation 1

Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.

From the question,

Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°

Substitute these values into equation 1

F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)

Since sin0° = 0,

Therefore,

F = 0 N

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A polarized light that has an intensity I0 = 52.0 W/m² is incident on four polarizing disks whose planes are parallel and center
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Answer:

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Explanation:

Given :

Incident intensity = 52 W/m^2

Angle between the transmission axis and polarizer optic axis = 18°

According to the malus law, when unpolarized or polarized light passes through polarizing disk, the intensity of the transmitted light is directly proportional to the square of the cosine of angle between the transmission axis and polarizer optic axis.

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Where I= transmitted intensity, I'= incident intensity, \alpha = angle between the transmission axis and polarizer optic axis.

Here, there are four polarizing disks so that.

from first disk,

∴ I₁ = 52 (cos)^2 18°

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