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Alisiya [41]
2 years ago
8

20 points and brainliest‼️‼️‼️‼️

Physics
1 answer:
Anastasy [175]2 years ago
3 0

Answer:

0 N

Explanation:

Applying,

F = qvBsin∅................. Equation 1

Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.

From the question,

Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°

Substitute these values into equation 1

F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)

Since sin0° = 0,

Therefore,

F = 0 N

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Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
Not everything in science is clear-cut, with obvious problems, experiments, theories, and solutions. Sometimes scientists gather
sergij07 [2.7K]
A. science sometimes requires creativity
4 0
2 years ago
A 6.00 A current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has 8.5×1028 free elect
navik [9.2K]

Answer:

Explanation:

Current, I = 6 A

diameter of wire, d = 2.05 mm

number of electrons per unit volume, n = 8.5 x 10^28

If the diameter is doubled,

The resistance of the wire is inversely proportional to the square of the diameter of the wire, so the resistance is  one forth an the current is directly proportional to the diameter of the wire so the current is four times the initial value.  

8 0
3 years ago
All objects near the earths surface - regardless of size and weight - hhave the same force of gravityvacting on them.
masya89 [10]

Answer:

B. False

Explanation:

Not all objects near the earths surface - regardless of size and weight - have the same force of gravity on them.

4 0
3 years ago
classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 128 feet per
ddd [48]

Answer:

t_1 = 0.28 s

t_2 = 7.72 s

Explanation:

Given that height of the projectile as a function of time is

h = -16 t^2 + 128 t + 112

here we know that

h = 147 ft

so from above equation

147 = -16 t^2 + 128 t + 112

16 t^2 - 128 t + 35 = 0

now by solving above quadratic equation we know that

t_1 = 0.28 s

t_2 = 7.72 s

6 0
2 years ago
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