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3 years ago

Describe three devices used in radiation detection

1 answer:

6 0

MicroR Meter, with Sodium Iodide Detector
Geiger Counter, with Geiger-Mueller (GM) Tube or Probe
Portable Multichannel Analyzer

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Please someone help me Balance this equation.

NeTakaya

Answer: This is an oxidation-reduction (redox) reaction:

3 C-II - 12 e- → 3 CII (oxidation)

4 CrVI + 12 e- → 4 CrIII (reduction)

C2H5OH is a reducing agent, K2Cr2O7 is an oxidizing agent.

7 0

2 years ago

The phenomenon of marble cancer is due to (a) soot particles (c) fog (b) CFCs (d) acid rain

Scorpion4ik [409]

Answer:

The phenomenon of marble cancer is due to ACID RAIN.

Explanation:

The marble corrosion is a process by which the marbles or limestone used in construction of monuments and buildings is corroded away by the acid rain. The sulphur-dioxide and nitrogen oxides present in the atmosphere undergoes certain chemical reaction causing this acid rain. These chemical in the acid rain converts the calcium present in the limestone or marble into salt.

Also, this marble cancer leads to change the appearance and color. Sometime due to over corrosion the monuments or building causes them disintegrate .Tajmahal is one of the monument affected by marble cancer. the white color of tai mahal is slowly turning into yellow due to this marble cancer.

3 0

3 years ago

Microwave ovens heat food by creating microwave electromagnetic radiation that is absorbed by water molecules in the food.

Nikolay [14]

Explanation:

It is known that relation between heat energy and temperature change is as follows.

Q = $mC \Delta T$

where, q = heat energy

m = mass of the solution or solvent

$\Delta T$ = change in temperature

Hence, putting the given values into the above formula as follows.

Q = $mC \Delta T$

= $110.0 g \times \frac{315 J}{75^{o}C} \times (100 - 25)^{o}C$

= 34650 J

Now, calculate the energy of photons at wavelength 3.02 mm as follows.

E = $\frac{hc}{\lambda}$

where, h = planks constant = $6.626 \times 10^{-34} Js$

c = velocity of light = $3 \times 10^{8}$ m/s

$\lambda$ = wavelength = 3.02 mm = $3.02 \times 10^{-3}$ m (as 1 m = 1000 mm)

Therefore, putting the given values into the above formula as follows.

E = $\frac{hc}{\lambda}$

= $\frac{6.626 \times 10^{-34} Js \times 3 \times 10^{8} m/s}{3.02 \times 10^{-3} m}$

= $6.58 \times 10^{-23}$ J

Now, the number of photons required of energy $6.58 \times 10^{-23}$ J/photon for the total energy of 34650 J as follows.

$E_{total} = n \times E$

n = $\frac{E_{total}}{E}$

= $\frac{34650 J}{6.58 \times 10^{-23}}$

= $5265.95 \times 10^{23}$ photons

or, = $5.265 \times 10^{26}$ photons

Thus, we can conclude that the minimum number of photons present are $5.265 \times 10^{26}$ .

7 0

3 years ago

LOOK AT THE IMAGE ABOVE CAN SOMEONE PLEASE HELP ME AND SHOW FULL STEPS PLEASE

Tju [1.3M]

answer:

explanation:

cause you dumb

5 0

2 years ago

A 0.025-g sample of a compound composed of Boron and hydrogen with the molecular mass of 28 AMU burns spontaneously when exposed

nalin [4]

Answer:

The empirical formula is BH₃ and molecular formula is B₂H₆

Explanation:

To know the number of borons you must obtain the moles number of the initial and B₂O₃ compound. So:

Moles of initial compound:

0,025 g of X × ( 1 mol / 28 g) = 8,9 × 10⁻⁴ moles

Moles of B₂O₃ compound:

AMU of B₂O₃ = (2 × 10,8 g/mol + 3 × 16 g/mol) = 69,6 g/mol

0,063 g ( 1 mol B₂O₃ / 69,6 g) = 9,1 × 10⁻⁴ moles

As moles number of initial and final compounds are the same, the number of borons must be equals. So, our compound has two borons.

These two borons weight: 2 × 10,8 g/mol = 21,6 g/mol

If UMA number of our compound is 28 g/mol we need, yet,

28 g/mol - 21,6 g/mol = 6,4 g/mol

These 6,4 g/mol comes from hydrogen that weights 1 g/mol. So, we have 6 hydrogens.

Thus, the molecular formula is B₂H₆

The empirical formula is the simplest way to represent the atoms of a chemical compound. If we divide the molecular formula in two, we will obtain the empirical formula: BH₃

I hope it helps!

4 0

3 years ago