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Damm [24]
3 years ago
5

When a chemist collects hydrogen gas over water, she ends up with a mixture of hydrogen and water vapor in her collecting bottle

If the pressure in the collecting bottle is 97.1 kilopascals and the vapor pressure of the water is 3 2 kilopascals, what is the partial pressure of the hydrogen?
Chemistry
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

i think he is correct but i also think its b

Explanation:

elixir [45]3 years ago
5 0

<u>Answer:</u> The partial pressure of hydrogen is 93.9 kPa.

<u>Explanation:</u>

To calculate the partial pressure of hydrogen, we will follow Dalton's Law.

This law states that the total pressure of a mixture of gases is equal to the sum of the individual pressures exerted by the constituent gases.

Mathematically,

p_{total}=p_A+p_B

According to the question,

p_{total}=p_{H_2O}+p_{H_2}

We are given:

p_{total}=97.1 kPa

p_{H_2O}=3.2kPa

p_{H_2}= ?kPa

Putting values in above equation, we get:

97.1kPa=3.2kPa+p_{H_2}

p_{H_2}= 93.9kPa

Hence, the partial pressure of hydrogen is 93.9 kPa.

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choli [55]

Answer:

22:

Formular:

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23:

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3 years ago
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What is the entropy change for the freezing process of 1 mole of liquid methanol at its freezing temperature (–97.6˚C) and 1 atm
Rudiy27

Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K

Explanation :

Formula used :

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where,

\Delta S = change in entropy

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As we know that:

\Delta H_{fus}=-\Delta H_{freezing}=-3.17kJ/mol=-3170J/mol

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Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{freezing}}{T_m}

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Sav [38]

<em>Answer:</em>

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According to rules of significant figure

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<em>50.0 m  have 3 significant figure:</em>

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<em>4500.01 ml have 6 significant figure:</em>

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