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Damm [24]
3 years ago
5

When a chemist collects hydrogen gas over water, she ends up with a mixture of hydrogen and water vapor in her collecting bottle

If the pressure in the collecting bottle is 97.1 kilopascals and the vapor pressure of the water is 3 2 kilopascals, what is the partial pressure of the hydrogen?
Chemistry
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

i think he is correct but i also think its b

Explanation:

elixir [45]3 years ago
5 0

<u>Answer:</u> The partial pressure of hydrogen is 93.9 kPa.

<u>Explanation:</u>

To calculate the partial pressure of hydrogen, we will follow Dalton's Law.

This law states that the total pressure of a mixture of gases is equal to the sum of the individual pressures exerted by the constituent gases.

Mathematically,

p_{total}=p_A+p_B

According to the question,

p_{total}=p_{H_2O}+p_{H_2}

We are given:

p_{total}=97.1 kPa

p_{H_2O}=3.2kPa

p_{H_2}= ?kPa

Putting values in above equation, we get:

97.1kPa=3.2kPa+p_{H_2}

p_{H_2}= 93.9kPa

Hence, the partial pressure of hydrogen is 93.9 kPa.

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The density of the fat tristearin is 0.95 g cm−3 . Calculate the change in molar Gibbs energy of tristearin when a deep-sea crea
KatRina [158]

The formula for the change in Gibbs energy of a solid is:

ΔG = Vm ΔP

where, ΔG is change in Gibbs, Vm is molar volume, ΔP is change in pressure

ΔP = P(final) – P(initial)

P(final) = 1 atm = 101325 Pa

P(initial) = ρ_water *g *h = (1030 kg/m^3) * 9.8 m/s^2 * 2000 m = 20188000 kg m/s^2 = 20188000 Pa

Vm = (950 kg/m^3) * (1000 mol / 891.48 kg) = 1065.64 mol/m^3

 

So,

ΔG = (1065.64 mol/m^3) * (101325 Pa - 20188000 Pa)

<span>ΔG = -21405164347 J = -21.4 GJ</span>

8 0
4 years ago
Question 1 (1 point)
Strike441 [17]

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Scientist used models to explain and predict the behavior of real object or system

3 0
3 years ago
ROY G BIV arranges the colors of the rainbow *
Elanso [62]

Answer:

Wavelengths..

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8 0
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Masja [62]

Answer:

May be the instrument is incorrect or may be error in it.

Explanation:

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