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Damm [24]
3 years ago
5

When a chemist collects hydrogen gas over water, she ends up with a mixture of hydrogen and water vapor in her collecting bottle

If the pressure in the collecting bottle is 97.1 kilopascals and the vapor pressure of the water is 3 2 kilopascals, what is the partial pressure of the hydrogen?
Chemistry
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

i think he is correct but i also think its b

Explanation:

elixir [45]3 years ago
5 0

<u>Answer:</u> The partial pressure of hydrogen is 93.9 kPa.

<u>Explanation:</u>

To calculate the partial pressure of hydrogen, we will follow Dalton's Law.

This law states that the total pressure of a mixture of gases is equal to the sum of the individual pressures exerted by the constituent gases.

Mathematically,

p_{total}=p_A+p_B

According to the question,

p_{total}=p_{H_2O}+p_{H_2}

We are given:

p_{total}=97.1 kPa

p_{H_2O}=3.2kPa

p_{H_2}= ?kPa

Putting values in above equation, we get:

97.1kPa=3.2kPa+p_{H_2}

p_{H_2}= 93.9kPa

Hence, the partial pressure of hydrogen is 93.9 kPa.

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If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K and then I raise the pressu
mixas84 [53]

Answer:

The answer to your question is V2 = 29.6 l

Explanation:

Data

Pressure 1 = P1 = 12 atm

Volume 1 = V1 = 23 l

Temperature 1 = T1 = 200 °K

Pressure 2 = 14 atm

Volume 2 = V2 = =

Temperature 2 = T2 = 300°K

Process

1.- To solve this problem use the Combine gas law.

             P1V1/T1 = P2V2/T2

-Solve for V2

             V2 = P1V1T2 / T1P2

2.- Substitution

             V2 = (12)(23)(300) / (200)(14)

3.- Simplification

             V2 = 82800 / 2800

4.- Result

            V2 = 29.6 l

5 0
3 years ago
The concentration of urea in a solution prepared by dissolving 16 g of urea in 20 g of H2OH2O is ________% by mass. The molar ma
Arada [10]

Answer:

44

Explanation:

Given that :

Mass of solute = Mass of urea = 16g

Mass of water = 20g

Mass of solution = (mass of solute + mass of solvent) = (mass of urea + mass of water) = (16g + 20g) = 36g

Percentage Mass = (mass of solute / mass of solution) * 100%

Percentage Mass = (16 / 36) * 100%

Percentage Mass = 0.4444444 x 100%

Percentage Mass = 44.44%

Percentage Mass = 44%

4 0
3 years ago
Question 2
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H2O (s) ⇒ H2O What would be the best argument against writing this in the form of a chemical equation?
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Answer: Since this is merely a Physical Change, it is improper to write it as a chemical equation.

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A student left a sealed jar of water outside her home. Water can be a solid, liquid, or gas. When she put it outside, the water
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The water molecules received enough energy through the heat for them to change to a liquid state by unfixing themselves from their fixed positions.

3 0
3 years ago
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