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miskamm [114]
2 years ago
6

A cross country skier moves 32 m north, then 65 m south, and finally 16 m north. What is the distance? What is the displacement

?
Physics
1 answer:
Fofino [41]2 years ago
4 0

The distance and Displacement travelled by skier is 17m and 16 m

<h3>What is Distance and Displacement?</h3>

Distance is the length of the actual path taken by object.

Displacement is the shortest distance between the initial and final position.

The SI unit of both distance and displacements is meter (m).

In this case,

Distance = 32m - 65m + 16 m

                 = 17 m

Here ,

Displacement  = Initial position - Final position

= 32m -16m  = 16m

Hence , The distance and displacement of the skier are 17m and 16m.

For more distance and displacement queries visit:

brainly.com/question/18965361

#SPJ1

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An object is initially moving at an unknown velocity. It accelerates at a rate of 1.5m/s2 to a new velocity of 60 m/s in 25 s. W
Alexandra [31]
<h3>Answer:  22.5 m/s</h3>

=====================================================

Work Shown:

acceleration = ( finalVelocity - initialVelocity )/(change in time)

1.5 = (60 - x)/(25)

1.5*25 = 60-x

37.5 = 60-x

x = 60-37.5

x = 22.5

The initial velocity is 22.5 m/s

6 0
3 years ago
Listed in the Item Bank are individual steps that need to be ordered. To find out more information about steps, some have more d
lapo4ka [179]

Answer:

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8 0
3 years ago
If a spacecraft is pushed by a thruster, what will happen
ElenaW [278]
D.

This is an accordance with Newton's First Law of Motion, stating that objects in motion remain in motion and objects at rest remain at rest unless acted upon by an external force.
8 0
3 years ago
A car traveling on a level road initially has 440 kJ of mechanical energy. After the brakes are applied for a few seconds, the c
Anvisha [2.4K]

Answer:

Explanation:

Given that

There's a change in friction from 440 kJ to 110 kJ

This change is as a result of conversion of energy. The energy of the car system converted the mechanical energy in it, into a corresponding heat energy. During the course of this conversion, is where a whopping 330 kJ of energy went missing.

The 330 kJ of energy was lost as a result of the conversion of mechanical energy into heat energy by the use of friction.

3 0
2 years ago
A compressor receives air at 290 K, 100 kPa and a shaft work of 5.5 kW from a gasoline engine. It is to deliver a mass flow rate
Sladkaya [172]

Answer:

P_2=4091\ KPa

Explanation:

Given that

T₁ = 290 K

P₁ = 100 KPa

Power P =5.5 KW

mass flow rate

\dot{m}= 0.01\ kg/s

Lets take the exit temperature = T₂

We know that

P=\dot{m}\ C_p (T_2-T_1)

5.5=0.01\times 1.005(T_2-290})\\T_2=\dfrac{5.5}{0.01\times 1.005}+290\ K\\\\T_2=837.26\ K

If we assume that process inside the compressor is adiabatic then we can say that

\dfrac{T_2}{T_1}=\left(\dfrac{P_2}{P_1}\right)^{0.285}

\dfrac{837.26}{290}=\left(\dfrac{P_2}{100}\right)^{0.285}\\2.88=\left(\dfrac{P_2}{100}\right)^{0.285}\\

2.88^{\frac{1}{0.285}}=\dfrac{P_2}{100}

P_2=40.91\times 100 \ KPa

P_2=4091\ KPa

That is why the exit pressure will be 4091 KPa.

4 0
3 years ago
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