Ask question

Ask question

All categories

3 years ago

6

The fact that the sun exerts a force on you, even though it it very far away, is a consequence of the Universal Law of _________

_.

2 answers:

Mashutka [201]3 years ago

6 0

the answer is gravitation :D

Elodia [21]3 years ago

4 0

Gravitation, gravity won't work, it has to be gravitation

You might be interested in

An circuit has a section AB as shown in the fig. with E= 10V. (sf C_1) = 1.0 F, (sf C_2) = 2.0 F and the potential difference (s

bagirrra123 [75]

Without the fig, we know nothing about AB, C_1, C_2, V_a, or V_b.
The probability of getting any kind of answer from anybody who hasn't
seen or tasted the fig is vanishingly small.

4 0

3 years ago

A softball is hit into the outfield during a game. The initial velocity is 33.52 m/s, and the ball is hit at an angle of 27°. Ho

Karo-lina-s [1.5K]

Answer:

weeeeeeeeeebeeeeeeeeeeeeeee

Explanation:

weeeeeeeeeee

7 0

2 years ago

Please just give me an answer, thanks.

Colt1911 [192]

#1

$\\ \rm\dashrightarrow P=VI\implies V=\dfrac{P}{I}$

$\\ \rm\dashrightarrow V=\dfrac{0.4\times 10^3}{33\times 10^{-3}}$

$\\ \rm\dashrightarrow V=0.012\times 10^{-6}$

$\\ \rm\dashrightarrow V=12mV$

#2

$\\ \rm\dashrightarrow R=\rho \dfrac{\ell}{A}$

$\\ \rm\dashrightarrow \rho =\dfrac{RA}{\ell}$

$\\ \rm\dashrightarrow \rho=\dfrac{86.3(0.4\times 10^6)}{69}$

$\\ \rm\dashrightarrow \rho=0.5\times 10^{6}$

It should be silicon

#3

Ohms law

$\\ \rm\dashrightarrow R=\dfrac{V}{I}$

$\\ \rm\dashrightarrow R=\dfrac{7(10^3)}{6(10^{-6})}$

$\\ \rm\dashrightarrow R=1.167\times 10^9\Omega$

7 0

2 years ago

I need to know what a-e is. Please and thank you!

beks73 [17]

The different types of energy transfers are convection, conduction, and radiation.
I'm not too sure on the second one but thermodynamics relates thermal energy, kinetic energy, and potential energy. I'm basing this on the formulas of the laws of thermodynamics, but it could also be temperature, heat, or work.

6 0

3 years ago

A point charge q = +4.50 nC moves through a potential difference ΔV = Vf − Vi = +27.0 V. What is the change in the electric pote

olganol [36]

Change in electric potential energy: 121.5 nJ

Explanation:

For a charged particle moving in an electric field, the change in electric potential energy of the particle is given by

$\Delta U = q \Delta V$

where:

q is the charge of the particle

$\Delta V$ is the potential difference between the initial and final position of the particle

For the point charge in this problem, we have:

$q=+4.50 nC$ is the charge

$\Delta V=+27.0 V$ is the potential difference

Therefore, the change in electric potential energy is

$\Delta U=(+4.50)(+27.0)=121.5 nJ$

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

6 0

3 years ago