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makvit [3.9K]
3 years ago
10

What is the first step dealing with an injured relationship

Physics
2 answers:
RideAnS [48]3 years ago
7 0
Well there is two if u are badly injured go check it out if u are a bit hurt rest it while having ice on it
Alex_Xolod [135]3 years ago
6 0
Communicate your issues and agree on a solution
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A 5.0 kg mass is suspended from a spring. Pulling the mass down by an additional 10 cm takes a force of 20 N. If the mass is the
Rudik [331]

Answer:

0.99 seconds

Explanation:

The problem depicts a simple harmonic motion.

Now, from Hooke's law,

The spring constant is given as;

k =F/x

where:

x is the displacement of the spring's end from its equilibrium position

F is the restoring force exerted by the spring on that end

From the question, F = 20N while x = 10cm = 0.1m. Thus,

K = 20/0.1 = 200 N/m

Now, time to take for the mass to return to its starting point is a period

The period oscillation of the mass is given as;

T = 2π√m/k

Where m = mass = 5kg

T = 2π√(5/200)

T = 0.99 s

4 0
2 years ago
Compare positive reinforcement and negative reinforcement.
Sergeeva-Olga [200]
Positive reinforcement you give praise and treats when they get something right negative you punish them for getting something wrong. Positive builds confidence and drive to get something right and negative builds fear of doing something wrong
4 0
2 years ago
Speed training increases one's maximum velocity.<br> a. True<br> b. False
Harrizon [31]
That is absolutely true.
3 0
3 years ago
Read 2 more answers
State Archimedes' principle
OlgaM077 [116]

Explanation:

Archimedes' principle states that the upward buoyant force which is exerted on body when immersed  whether fully submerged or partially in the fluid is equal to weight of fluid which body displaces and this force acts in upward direction at center of mass of displaced fluid.

Thus,

<u>Weight of the displaced fluid = Weight of the object - Weight of object in fluid.</u>

6 0
3 years ago
The energy released from condensation in thunderstorms can be very large. Calculate the energy (in J) released into the atmosphe
makkiz [27]

Answer:

7.19 * 10^14J

Explanation:

Given that

Density of water Pwater= 1000kg/m3

R=2.1km = 2.1*10^3m

H= 2.3cm. = 2.3*10^-2m

Lv water= 2256 * 10^3J/kg

First, mass of water need to be calculated, using an imaginary cylinder

Density= Mass /Volume

Mass= Density* Volume

Volume of a cylinder= πR2h

Therefore mass= PπR2H

= 1000 * π * (2.1 *10^3)^2 * (2.3 * 10^-2)

= 3.18 *10^8

Heat Released Qv = mLV

= 3.18*10^8 * 2236*10^3

= 7.19 * 10^14J

7 0
3 years ago
Read 2 more answers
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