Answer:
0.99 seconds
Explanation:
The problem depicts a simple harmonic motion.
Now, from Hooke's law,
The spring constant is given as;
k =F/x
where:
x is the displacement of the spring's end from its equilibrium position
F is the restoring force exerted by the spring on that end
From the question, F = 20N while x = 10cm = 0.1m. Thus,
K = 20/0.1 = 200 N/m
Now, time to take for the mass to return to its starting point is a period
The period oscillation of the mass is given as;
T = 2π√m/k
Where m = mass = 5kg
T = 2π√(5/200)
T = 0.99 s
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Explanation:
Archimedes' principle states that the upward buoyant force which is exerted on body when immersed whether fully submerged or partially in the fluid is equal to weight of fluid which body displaces and this force acts in upward direction at center of mass of displaced fluid.
Thus,
<u>Weight of the displaced fluid = Weight of the object - Weight of object in fluid.</u>
Answer:
7.19 * 10^14J
Explanation:
Given that
Density of water Pwater= 1000kg/m3
R=2.1km = 2.1*10^3m
H= 2.3cm. = 2.3*10^-2m
Lv water= 2256 * 10^3J/kg
First, mass of water need to be calculated, using an imaginary cylinder
Density= Mass /Volume
Mass= Density* Volume
Volume of a cylinder= πR2h
Therefore mass= PπR2H
= 1000 * π * (2.1 *10^3)^2 * (2.3 * 10^-2)
= 3.18 *10^8
Heat Released Qv = mLV
= 3.18*10^8 * 2236*10^3
= 7.19 * 10^14J
