All categories

3 years ago

What is the first step dealing with an injured relationship

Physics

2 answers:

RideAnS [48]3 years ago

7 0

Well there is two if u are badly injured go check it out if u are a bit hurt rest it while having ice on it

Alex_Xolod [135]3 years ago

6 0

Communicate your issues and agree on a solution

You might be interested in

Suppose mass and radius of the planet are half and twice that of earth's respectively. If acceleration due to gravity of the ear

stich3 [128]

Answer:

The acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

Explanation:

Given that,

Mass of the planet, m = 1/2M

Radius of the planet, r = 2R

Where M and R is the mass and radius of the Earth respectively.

The acceleration due to gravity of Earth, g = 10 m/s²

The acceleration due to gravity of Earth is given by the relation,

g = GM/R²

Similarly, the acceleration due to gravity of that planet is

gₐ = Gm/r²

where G is the Universal gravitational constant

On substituting the values in the above equation

gₐ = G (1/2 M)/4 R²

= GM/8R²

= 1/8 ( 10 m/s²)

= 1.25 m/s²

Hence, the acceleration due to gravity of that planet is, gₐ = 1.25 m/s²

3 0

4 years ago

To see if such a strong magnetic field could pose health risks for nearby workers, calculate the maximum acceleration the field

Evgesh-ka [11]

bro how do you not know this cmon bro what the actual heck dudeExplanation:

6 0

3 years ago

Charge q1 is distance r from a positive point charge Q. Charge q2=q1/3 is distance 2r from Q. What is the ratio U1/U2 of their p

worty [1.4K]

We have that The ratio U1/U2 of their potential energies due to their interactions with Q is

$U1/U2=6$
$U1/U2=6$

From the question we are told that

Question 1

Charge q1 is distance r from a positive point charge Q.

Question 2

Charge q2=q1/3 is distance 2r from Q.

Charge q1 is distance s from the negative plate of a parallel-plate capacitor.

Charge q2=q1/3 is distance 2s from the negative plate.

Generally the equation for the potential energy is mathematically given as

$U=\frac{-k*qQ}{r}$

Therefore

The Equations of U1 and U2 is

For U1

$U1=\frac{-k*q_1Q}{r}$

For U2

$U2=\frac{-k*q_1Q}{3*2r}$

Since

U is a function of q and q2=q1/3

Therefore

$U1/U2=6$

For Question 2

For U1

$U1=\frac{-k*q_1Q}{s}\\\\For U2\\\\U2=\frac{-k*q_1Q}{3*2r}$

Therefore

$U1/U2=6$

For more information on this visit

brainly.com/question/23379286?referrer=searchResults

7 0

3 years ago

In a container which can expand or contract (like a balloon, if the temperature of the gas increases, the volume of that gas ___

Usimov [2.4K]

B. Increases
hope this helps

5 0

4 years ago

Ur a genius if u explain how it’s A correctly

Alinara [238K]

Answer:

Explanation:

4/1=4

3/2=1.5

2/3=0.666667

1/4=0.25

D has the least number so its D

6 0

3 years ago