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julsineya [31]
4 years ago
5

How many moles of silver atoms are in 1.8 × 10^20 atoms of silver?

Chemistry
1 answer:
gavmur [86]4 years ago
6 0
1.8x10^20 atoms x (1 mole / 6.022x10^23 atoms) = 3.0x10^-4 mole 
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You have two beakers. One beaker contains 100 mL of NaOH (a strong base); the other contains 100 mL of aqueous Na3PO4 (a weak ba
Ilya [14]

Answer:

D. If the pH of NaOH is 12, then that of Na₃PO₄ solution has to be lesser than 12.

Explanation:

In this problem, we are comparing the pH of a strong base to a weak base. A strong base is one that ionizes completely in aqueous solutions where as a weak base ionizes slightly.

The pH scale is good tool for measuring the acidity and alkalinity of various substances. It ranges from 1 - 14;

   

      1                                      7                                               14

                         ←                                       →

      increasing acidity                          increasing alkalinity

                                        neutrality

Strong bases have their pH value close to 14 and weak bases are close to 7.

Since Na₃PO₄ is a weak base, it will have lesser pH value compared to a strong base such as NaOH

6 0
4 years ago
How to determine that a neutralization reaction is complete
Yuki888 [10]

Answer:

You can tell by looking at the reaction. If it stops bubbling or steaming it is finished. It s going to react and start bubbling. When it stops bubbling and fizzing, the reaction will be over.

8 0
2 years ago
N2 (g) + 3 H2 (g) → 2 NH3 (g)
shusha [124]

This problem is asking for the rate of disappearance of gaseous nitrogen, given the rate of appearance of ammonia and the chemical reaction. At the end, the result turns out to be -0.228 M/s.

<h3>Rates of appearance and disappearance</h3>

In chemical kinetics, one of the most relevant calculations are based on rates of appearance and disappearance of chemical species in a chemical reaction. This can be calculated via rate portions based on the stoichiometric coefficients in the reaction.

Thus, for this problem, one can write:

\frac{r_{N_2}}{-1} =\frac{r_{H_2}}{-3} =\frac{r_{NH_3}}{2}

Where the rate of appearance or disappearance is divided by the stoichiometric coefficient. Therefore, one can solve for the rate of disappearance of N2 with:

\frac{r_{N_2}}{-1} =\frac{r_{NH_3}}{2}\\\\r_{N_2}=\frac{r_{NH_3}*-1}{2}\\\\r_{N_2}=\frac{0.456M/s*-1}{2}\\\\r_{N_2}=-0.228M/s

Learn more about chemical kinetics: brainly.com/question/26351746

3 0
2 years ago
Aluminum has a density of 2.70g/cm what is the volume occupied by a block of aluminum which weights 4.32kg
romanna [79]

Answer:

Explanation:

0.000625 cm3  

  0.625 cm3  

  1.60 cm3

4 0
3 years ago
1) How many moles of gas occupy 58 L at a pressure of 2.2 atmospheres and a temperature
Sergio039 [100]

Here, we need to solve this problem using Ideal gas law ( PV=nRT).

Where –

  • P = Pressure in atm
  • V = Volume in L
  • n = moles
  • R = Ideal gas law constant
  • T = Temperature in K

<u>Now, according to the question </u>–

  • V = 58 L
  • P = 2.2 atm
  • T = 313 K
  • R = 0.0821 atm L/ mol K

<u>Calculation</u> –

\qquad \pink{\twoheadrightarrow\bf PV = nRT}

\qquad \twoheadrightarrow\sf n = \dfrac{PV}{RT}

\qquad \twoheadrightarrow\sf  n = \dfrac{ 2.2 \: \:\times 58 \: } {0.0821  \times 313}

\qquad \twoheadrightarrow\sf  n = \dfrac{ 2.2 \times 58}{0.0821 \times 313}

\qquad \twoheadrightarrow\sf  n =\dfrac{127.6}{25.7}

\qquad \pink{\twoheadrightarrow\bf  n = 4.9656 \: moles }

_______________________________________

8 0
3 years ago
Read 2 more answers
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