Answer:
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- <u><em>B) an error occurred, the mass of the reactants should equal the mass of the products. </em></u>
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Explanation:
The answer choices are:
- <em>A) no error occurred, some of the products are always lost as heat.</em>
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- <em>B) an error occurred, the mass of the reactants should equal the mass of the products. </em>
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- <em>C) an error occurred, the products should weigh more than the reactants. </em>
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- <em>D) no error occurred, water is not weighed when determining the weight of the products.</em>
<h2>Solution</h2>
The basis to answer this question is the law of conservation of mass.
Any chemical reaction satisfies the law of conservation of mass: mass cannot be either created nor destroyed, so, always, <em>the mass of the reactants equal the mass of the products.</em>
Thus, since he measured the mass of his reactant materials to be 35g and he reported that his products weighed 32g, his data are in clear contradiction of the law of conservation of mass. So, there is an error in his results: <em>the mass of the reactants should equal the mass of the products. </em>
X-rays differ from the light source readout in terms of the intensity and the possible damage that can be obtained from the two radiation types. The light source readout is more damaging than the X-rays readout in the gizmo. Therefore, precaution is required when handling the light source readout in the gizmo.
Answer:
M (third main energy level)
Explanation:
The third main energy level bears the first appearance of the 'd' sublevel. The principal quantum number(n) depicts the main energy levels in which an orbital is located. It takes values of n=1,2,3,4,5..... and it can be represented by the shells k,l,m,n.......
The subshells in these main orbitals are represented by s,p,d and f. For the K shell, the principal quantum number is m and its sublevel notations are s,p and d. This is where the d-sublevel first appears.
Answer:
Explanation:
From the given information:
The concentration of metal ions are:
![[Ca^{2+}]= \dfrac{0.003474 \ M \times 20.49 \ mL}{10.0 \ mL}](https://tex.z-dn.net/?f=%5BCa%5E%7B2%2B%7D%5D%3D%20%5Cdfrac%7B0.003474%20%5C%20M%20%5Ctimes%2020.49%20%5C%20mL%7D%7B10.0%20%5C%20mL%7D)
![[Ca^{2+}]=0.007118 \ M](https://tex.z-dn.net/?f=%5BCa%5E%7B2%2B%7D%5D%3D0.007118%20%5C%20M)
![[Mg^2+] = \dfrac{0.003474 \ M\times (26.23 - 20.49 )mL}{10.0 \ mL}](https://tex.z-dn.net/?f=%5BMg%5E2%2B%5D%20%3D%20%5Cdfrac%7B0.003474%20%5C%20M%5Ctimes%20%2826.23%20%20-%2020.49%20%29mL%7D%7B10.0%20%5C%20mL%7D)

Mass of Ca²⁺ in 2.00 L urine sample is:

= 0.1598 g
Mass of Ca²⁺ = 159.0 mg
Mass of Mg²⁺ in 2.00 L urine sample is:

= 0.3461 g
Mass of Mg²⁺ = 346.1 mg