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Anna007 [38]
3 years ago
5

i got the right answer for this question (pretty sure i guessed or just asked me teacher the answer?) but can someone explain ho

w i got that answer (like the process of figuring it out) thanks :)

Physics
2 answers:
loris [4]3 years ago
6 0
A guessing answer the best answer but you have had to subtract the answer by the equation that it was giving u
artcher [175]3 years ago
6 0

How you got the answer:

-- Either you guessed, or else you asked somebody else and they gave you the answer.  It really doesn't matter.  As you can see, whichever it was, you didn't learn anything in the process.

The helpful and correct way to solve the problem:

-- For any wave, <em>Speed = (frequency) x (wavelength)</em>

Whenever you're dealing with waves, and you know any two of those three quantities, you can always use this formula to calculate the quantity you don't know.

This problem GIVES you the speed and the wavelength.  USE this formula to calculate the frequency.

You might be interested in
Human eyes detect only a very small band of the electromagnetic spectrum. However, some animals and insects see in higher and lo
hoa [83]

Answer:

Squids = 450 - 490 nm (Moderate Frequency) (Blue)

Bees = 300 - 650 nm (Lower Frequency Bands)

Frogs = 280 - 580 nm (Very Low Frequency)

Explanation:

All of the above mentioned ranges are compared to that of humans.

I'm just surprised a little bit in the imagination that how these organisms see the world through their unique eyes. On the other hands, they are evolved like this just like we do so that may not be surprising enough. SIKE

3 0
3 years ago
What is the peak emf generated by rotating a 940-turn, 24 cm diameter coil in the Earth’s 5·10−5 T magnetic field, given th
elena-14-01-66 [18.8K]

Answer:

The peak emf generated by the coil is 2.67 V

Explanation:

Given;

number of turns, N = 940 turns

diameter, d = 24 cm = 0.24 m

magnetic field, B = 5 x 10⁻⁵ T

time, t = 5 ms = 5 x 10⁻³ s

peak emf, V₀ = ?

V₀ = NABω

Where;

N is the number of turns

A is the area

B is the magnetic field strength

ω is the angular velocity

V₀ = NABω and ω = 2πf = 2π/t

V₀ = NAB2π/t

A = πd²/4

V₀ = N x (πd²/4) x B x (2π/t)

V₀ = 940 x (π x 0.24²/4) x 5 x 10⁻⁵ x (2π/0.005)

V₀ = 940 x 0.04524 x  5 x 10⁻⁵ x 1256.8

V₀ = 2.6723 V = 2.67 V

The peak emf generated by the coil is 2.67 V

8 0
3 years ago
A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy
GREYUIT [131]

Answer:

21.21 m/s

Explanation:

Let KE₁ represent the initial kinetic energy.

Let v₁ represent the initial velocity.

Let KE₂ represent the final kinetic energy.

Let v₂ represent the final velocity.

Next, the data obtained from the question:

Initial velocity (v₁) = 15 m/s

Initial kinetic Energy (KE₁) = E

Final final energy (KE₂) = double the initial kinetic energy = 2E

Final velocity (v₂) =?

Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:

KE = ½mv²

NOTE: Mass (m) = constant (since we are considering the same car)

KE₁/v₁² = KE₂/v₂²

E /15² = 2E/v₂²

E/225 = 2E/v₂²

Cross multiply

E × v₂² = 225 × 2E

E × v₂² = 450E

Divide both side by E

v₂² = 450E /E

v₂² = 450

Take the square root of both side.

v₂ = √450

v₂ = 21.21 m/s

Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.

8 0
3 years ago
Gawaingnpang nkabuhayan,hamon at oportinidad​
Savatey [412]

gawaingnpang nkabuhayan, hamon at oportinidad

7 0
3 years ago
When the units are smaller,<br> we need (more / less) of them.
lbvjy [14]

Answer:

more..................

6 0
3 years ago
Read 2 more answers
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