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3 years ago

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An outfielder with a mass of 86 Kilograms catches a baseball with a mass of 0.15 kilograms.The velocity of the ball just before

being caught is 40 meters per second.What is the impulse imparted by the ball onto the outfielder?
A. 6.00 Ns
B. 3,440 Ns
C. 2.00 Ns
D. 3,434 Ns

1 answer:

nordsb [41]3 years ago

5 0

Answer:

C

Explanation:

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zalisa [80]

The correct answer is c) 28 m/s.
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from which
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Answer:

MRCORRECT has answered the question

Explanation:

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11111nata11111 [884]

Answer:

$3.13\times 10^{-5} C$

Explanation:

We are given that

$q_1=26\mu C=26\times 10^{-6} C$

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We have to find the magnitude of q2.

We know that

$F=\frac{kq_1q_2}{r^2}$

Where $k=9\times 10^9$

Using the formula

Force on charge q due to charge q1

$F_1=\frac{9\times 10^9\times 26\times 10^{-6}\times 8.1\times 10^{-6}}{(0.21)^2}$

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Force on charge q due to point charge q2

$F_2=\frac{9\times 10^9\times q_2\times 8.1\times 10^{-6}}{(0.39)^2}$

$F_2=4.79\times 10^5 q_2$

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$28=42.98-4.79\times 10^5q_2$

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$q_2=\frac{14.98}{4.79\times 10^5}=3.13\times 10^{-5} C$

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