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kenny6666 [7]
3 years ago
10

An outfielder with a mass of 86 Kilograms catches a baseball with a mass of 0.15 kilograms.The velocity of the ball just before

being caught is 40 meters per second.What is the impulse imparted by the ball onto the outfielder?
A. 6.00 Ns
B. 3,440 Ns
C. 2.00 Ns
D. 3,434 Ns
Physics
1 answer:
nordsb [41]3 years ago
5 0

Answer:

C

Explanation:

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You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic
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Answer:

Explanation:

Force of friction acting on the body = μ mg cosθ

= .4  x 70 x 9.8 x cos30

= 237.63 N

component of weight = mgsinθ

= 70 x 9.8 x sin30

= 343 N  

Net upward force = 600 - mgsinθ - μ mg cosθ

= 600 - 343 - 237.63

= 105.37 N

acceleration in upward direction = 105.37 / 70

= 1.5 m /s²

s = ut + 1/2 a t²

= 0 + .5 x 1.5 x 3²

= 6.75 m .

5 0
3 years ago
A 2300 kg sailboat is moving west at 5.5 m/s when an eastward wind
pogonyaev

The boat is initially at equilibrium since it seems to start off at a constant speed of 5.5 m/s. If the wind applies a force of 950 N, then it is applying an acceleration <em>a</em> of

950 N = (2300 kg) <em>a</em>

<em>a</em> = (950 N) / (2300 kg)

<em>a</em> ≈ 0.413 m/s²

Take east to be positive and west to be negative, so that the boat has an initial velocity of -5.5 m/s. Then after 11.5 s, the boat will attain a velocity of

<em>v</em> = -5.5 m/s + <em>a</em> (11.5 s)

<em>v</em> = -0.75 m/s

which means the wind slows the boat down to a velocity of 0.75 m/s westward.

5 0
3 years ago
Answers please!!!!!!!!!!!!!!!!
kaheart [24]
I only know #2 and #4.
2.) cells
3.) cells,  life , existing

Sorry that i dont know the rest but i took a test on this not to long ago, and i tend to forget stuff once i take a test on it.


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I have a question, it concerns hydrostatic buoyancy and Archimedes' law.
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Answer: the lvl wud remain the same

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marin [14]

Answer:

the answer is c

Explanation:

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3 years ago
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