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mars1129 [50]
3 years ago
11

Which component is used to measure the current in a circuit? A. switch B. resistor C. ammeter D. voltmeter

Physics
1 answer:
Nady [450]3 years ago
7 0

Answer:

The answer is C) amperemeter

Explanation:

An ammeter is made up of a galvanometer which is constructed with an indicator needle, a spring, a coil, and 2 permanent magnets and its operation is based on magnetism. The needle is attached by a spiral spring to the axis of a rectangular coil, which is suspended due to the magnetic field of the magnets.

Because the coil is controlled by the magnetic poles of the magnets when a current passes over it generates its own magnetic field which makes it turn depending on the meaning and force of this electrical intensity.

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When two waves are moving toward each other, and their crests line up with each other, it results in a wave with greater amplitu
Maurinko [17]

constructive interference

4 0
3 years ago
An object weighs 10N on earth .what is the objects weight on a planet one tenth the earths mass and one half its radius?
earnstyle [38]
We know, weight = mass * gravity 
10 = m * 9.8
m = 10/9.8 = 1.02 Kg

Now, Let, the gravity of that planet = g'
g' = m/r²   [m,r = mass & radius of that planet ]
g' = M/10 / (1/2R)²   [M, R = mass & radius of Earth ]
g' = 4M / 10R²
g' = 2/5 * M/R²
g' = 2/5 * g   
g' = 2/5 * 9.8
g' = 3.92

Weight on that planet = planet's gravity * mass
W' = 3.92 * 1.02
W' = 4 N

In short, Your Answer would be 4 Newtons

Hope this helps!
3 0
3 years ago
The radius of earth is 6,370,000 m. Express this measurement in km in scientific notation with the correct number of significant
AlexFokin [52]

Answer:

6.37 x 10³ Km

Explanation:

given,

Radius of earth = 6,370,000 m

we know,

1 km = 1000 m

1 m = 0.001 Km

6,370,000 m =  6,370,000 x 0.001

                       = 6,370 Km

The number 6,370 has 3 significant figure.

To transform this to an exponential number, it is necessary to move the decimal to the left so there is only one digit in front of the decimal point.

Representing the given number in scientific notation

      = 6.37 x 10³ Km

7 0
3 years ago
The half-life of Co-55 is 175 hours. How much of a 4000 g of Cobalt-55 sample would be left after 525 hours?
Harrizon [31]

We know that whatever amount we start with, half of it decays and forms atoms of other elements in 175 hours.  So in order to figure out how much is left after 525 hours, we'll need to know how many half-lifes pass in that amount of time.

Well, (525 divided by 175) is exactly 3 half-lifes.  So this will be easy.

-- After 1 half-life . . .

. . . . . 50% decays, 50% is still there.

-- After the 2nd half-life . . .

. . . . . (half of the leftover 50%) = another 25% decays, 25% is left.

-- After the 3rd half-life . . .

. . . . . (half of the leftover 25%) = another 12.5% decays, 12.5% is left.

12.5% of 4,000g = (0.125 x 4,000g) = <em>500 g</em> .

============================================

<u>Another way</u>:

After 1 half-life, 1/2 is left.

After 2 half-lifes, 1/4 is left.

After 3 half-lifes, 1/8 is left.

1/8 of 4,000g = (4,000g/8) = <em>500 g </em>.

5 0
2 years ago
Trick question (really easy) just for fun! If u get this right u get brainliest!
Maurinko [17]

Answer:

piper duh

Explanation:

6 0
2 years ago
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