Question

I NEED HELP PLEASE, THANKS! Light passes from air into water at an angle of 40.0° to the normal. What is the angle of refraction? Please show all work.

Answer 1

Answer:

Angle of Refraction = 28.9 degrees

Explanation:

We'll use Snell's law for this. It's mathematical form is:

=> $n_1* sin(\alpha _1)=n_2 * sin(\alpha _2)$

Where $n_{1} = 1, n_{2} = 1.33, \alpha _{2} = 40^o$

=> $n_{1}$ and $n_{2}$ are the refractive indexes of the air and water respectively.

Solution:

=> 1 * sin (40) = 1.33 * sin($\alpha _{2}$)

=> sin $\alpha _{2}$ = $\frac{sin 40^0}{1.33}$

=> sin $\alpha _{2}$ = 0.4821

=> $\alpha _{2}$ = 28.9 degrees