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schepotkina [342]
4 years ago
15

A bear spies some honey and takes off from rest, accelerating at a rate of 2.0 m/s^2. If the honey is 16m away, how fast will hi

s snout be going at the moment of ecstasy?
Physics
1 answer:
Anna11 [10]4 years ago
3 0

Answer:

8 m/s

Explanation:

From the third law of motion

v^{2}=u^{2}+2as where v is final velocity, u is initial velocity, a is acceleration, s is distance covered.

Since the bee takes off from rest, initial velocity is zero.

Substituting 0 for u, the equation becomes

v^{2}=0+2as=2as and making v the subject of the formula

v=\sqrt {2as}

Substituting 2 for a and 16 m for s

v=\sqrt {2*2*16}

v=8 m/s

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