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Anton [14]
3 years ago
10

What Is the name of the force that holds together the sub Tomic particles of the nuclear?

Chemistry
1 answer:
Alborosie3 years ago
6 0

the nucleus of an atom is held together by the strong force, while the electrons are held in the atom by the electric force.

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5. calculate the percentage of water of crystallization in blue vitriol (copper sulphate pentahydrate), cuso4.5h2o
ki77a [65]

The percentage of water of crystallization in blue vitriol is 36.07%.

M(H₂O) = 2Ar(H) + Ar(O) x g/mol

M(H₂O) = 2 + 16 x g/mol

M(H₂O) = 18 g/mol; molar mass of water

M(CuSO₄·5H₂O) = Ar(Cu) + Ar(S) + 4Ar(O) + 5Mr(H₂O) x g/mol

M(CuSO₄·5H₂O) = 63.5 + 32 + 64 + 90 x g/mol

M(CuSO₄·5H₂O) = 249.5 g/mol; molar mass of copper sulphate pentahydrate

The percentage of water: 5M(H₂O) / M(CuSO₄·5H₂O) x 100%

The percentage of water: 90 g/mol / 249.5 g/mol x 100%

The percentage of water = 36.07%

More about blue vitriol: brainly.com/question/8895853

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5 0
1 year ago
Read 2 more answers
Read the passage below and choose the best answer for the main idea of the passage:
Crank

Answer: C

Explanation:

4 0
3 years ago
True or False: Photosynthesis can happen anytime, regardless of the amount of reactants present or the presence of sunlight.
Arisa [49]
The answer is false .
3 0
3 years ago
Read 2 more answers
.7 liters of CO represents how many molecules?
Ronch [10]

Answer:

               1.88 × 10²² Molecules of CO

Explanation:

At STP for an ideal gas,

Volume = Mole × 22.4 L/mol

Or,

Mole = Volume / 22.4 L/mol

Mole = 0.7 L / 22.4 L/mol

Mole = 0.03125 moles

Now,

No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol

No. of Molecules = 0.03125 × 6.022 × 10²³ Molecules/mol

No. of Molecules = 1.88 × 10²² Molecules of CO

7 0
2 years ago
I need help with B and C
lakkis [162]
B) Mg is the alkaline earth metal w/12 protons so following the periodic table to the halogen in the same period is

Cl: Chlorine

C) The Neutral noble has w/ 18 electrons is argon so the metal in the same row is

Na: Sodium
8 0
3 years ago
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