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Dafna11 [192]
3 years ago
12

why do the products of multidigit numbers with zeros & one digit sometimes have zeros in them & sometimes have no zeros

in them?
Mathematics
2 answers:
Monica [59]3 years ago
6 0
No too sure.....there are a bunch of math people who can help you on YouTube!! I would suggest you watching "mathantics.com" he has a bunch of stuff if you still need help!
Bingel [31]3 years ago
3 0
Im not quite triggered but U should go to mathantics.com or watch his videos to find it out :D
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Help me plsss! Thank you
Brrunno [24]

You want to calculate the interest on $3020 at 5% interest per year after 6 6 month period(s).

The formula we'll use for this is the simple interest formula, or:

Where:

P is the principal amount, $3020.00.

r is the interest rate, 5% per year, or in decimal form, 5/100=0.05.

t is the time involved, 6....6 month period(s) time periods.

Since your interest rate is "per year" and you gave your time interval in "6 month period(s)" we need to convert your time interval into "year" as well.

Do this by dividing your time, 6- 6 month period(s), by two (2), since there's two 6-month periods in 1 year.

So, t is 3....year time periods.

To find the simple interest, we multiply 3020 × 0.05 × 3 to get that:

The interest is: $453.00

Usually now, the interest is added onto the principal to figure some new amount after 6 6 month period(s),  

or 3020.00 + 453.00 = 3473.00. For example:

If you borrowed the $3020.00, you would now owe $3473.00

If you loaned someone $3020.00, you would now be due $3473.00

If owned something, like a $3020.00 bond, it would be worth $3473.00 now.

4 0
3 years ago
Read 2 more answers
Find the missing terms in the following sequence 2,4,8,16,30, , , , 186,
ivann1987 [24]
Are you sure it is correct because for each one your just doubling the number. 2+2=4. 4+4=8. 8+8=16. I think its suppose to be 16+16= 32 and so on, but I may be wrong
5 0
3 years ago
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
kathy plans to bake 2 types of cookies to take to the party. She needs to be sure she has enough ingredients. The chocolate chip
myrzilka [38]

Answer:

4 11/12

I hope I helped! (If I got it wrong, feel free to tell me I got it wrong)

7 0
3 years ago
Find the area. 1m 2.1m and 0.9m
Elina [12.6K]
Just multiply w*l*h
1.89m cubed
6 0
3 years ago
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