All categories

3 years ago

X-rays of epiphyses enable doctors to estimate children’s ________

Physics

1 answer:

Mars2501 [29]3 years ago

7 0

<h3><u>Answer;</u></h3>

Skeletal age

<h3><u>Explanation;</u></h3>

Epiphyses are the rounded portions at the ends of a bone separated from the metaphysis by the physis. The epiphysis contributes to a joint, compared with an apophysis which is a site of tendon or ligament attachment.
A bone age study helps doctors estimate the maturity of a child's skeletal system. It's usually done by taking a single X-ray of the left wrist, hand, and fingers.

You might be interested in

Jimena is stopped at a red light. When the light turns green, she

Ludmilka [50]

First one accelerated

8 0

2 years ago

What is the slowest type of radiation?

tekilochka [14]

Velocity is the answer

3 0

3 years ago

Lunar eclipse

vichka [17]

Answer:

Hey

Your answer would be

The moon is not visible

due to Earth's shadow=lunar eclipse

The sun is not visible due

to the moon=solar eclipse

The moon is on the side of

Earth opposite the sun=new moon

The moon and sun are on

the same side of Earth=full mon

4 0

3 years ago

A block of mass 0.1 kg is attached to a spring of spring constant 21 N/m on a frictionless track. The block moves in simple harm

bogdanovich [222]

Answer:

A) 2.75 m/s B) 0.1911 m C) 0.109 s

Explanation:

mass of block = M =0.1 kg

spring constant = k = 21 N/m

amplitude = A = 0.19 m

mass of bullet = m = 1.45 g = 0.00145 kg

velocity of bullet = vᵇ = 68 m/s

as we know:

Angular frequency of S.H.M = ω₀ = $\sqrt\frac{k}{M}$

= $\sqrt\frac{21}{0.1}$

= 14.49 rad/sec

<h3>A) Speed of the block immediately before the collision:</h3>

displacement of Simple Harmonic Motion is given as:

$x = A sin (\omega t + \phi)\\$

Differentiating this to find speed of the block immediately before the collision:

$v=\frac{dx}{dt}= A\omega_{o} cos (\omega_{o}t =\phi}\\$

As bullet strikes at equilibrium position so,

φ = 0

t= 2nπ

⇒ cos (ω₀t + φ) = 1

⇒ $v= A\omega_{o}$

$v=(.19)(14.49)\\v= 2.75 ms^{-1}$

<h3>B) If the simple harmonic motion after the collision is described by x = B sin(ωt + φ), new amplitude B:</h3>

S.H.M after collision is given as :

$x= Bsin(\omega t + \phi)$

To find B, consider law of conservation of energy

$K.E = P.E\\K.E= \frac{1}{2}(m+M)v^{2} \\P.E = \frac{1}{2} kB^{2}$

$\frac{m+M}{k} v^{2} = B^{2} \\B =\sqrt\frac{m+M}{k} v\\B = \sqrt\frac{.00145+0.1}{21} (2.75)\\B = .1911m$

<h3>C) Time taken by the block to reach maximum amplitude after the collision:</h3>

Time period S.H.M is given as:

$T=2\pi \sqrt\frac{m}{k}\\ for given case\\m= m=M\\then\\T=2\pi \sqrt\frac{m+M}{k}$

Collision occurred at equilibrium position so time taken by block to reach maximum amplitude is equal to one fourth of total time period

$T=\frac{\pi }{2}\sqrt\frac{m+M}{k} \\T=0.109 sec$

5 0

3 years ago

Explain why the temperature for freezing point and boiling point are the same.

Tasya [4]

We have to wonder what substance you're working with. Under normal, human environmental conditions, there are almost no substances that freeze and boil at the same temperature.

However, EVERY substance has SOME temperature, at some pressure, at which it "sublimes" ... passing directly from solid to gas, or from gas to solid, without existing in liquid form in between. Even water does that, if the conditions are right.

7 0

3 years ago

Read 2 more answers