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Harlamova29_29 [7]
3 years ago
11

What is the change in internal energy (in J) of a system that releases 675 J of thermal energy to its surroundings and has 525 c

al of work done on it
Physics
1 answer:
Savatey [412]3 years ago
6 0

Answer:

1519.5 joules

Explanation:

What is the change in internal energy (in J) of a system that releases 675 J of thermal energy to its surroundings and has 525 cal of work done on it

first, convert cal to joules

1 cal =4.18 joules

so 525 cal = 525 X 4.18 = 2194.5 joules

the system spent 675 joules heating the surroundings and was given

2194.5 joules by work done on it

so the net gain in energy is

2194.5 -675 = 1519.5 joules

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Answer:

To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.

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Thus with an average density of 2.8gram per centimeter cube

50*2.8= (50-x)*3.16

(50-x)= (50*2.8)/3.16

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Explanation:

To calculate the predicted surface elevation of a 50km thick crust above a surface of 2.5km we are given a density of 3 gram per centimeter cube.

The displacement of the material will be calculated by subtracting the surface elevation of 2.5 km from the 50 km thick crust. Therefore 50-25= 47.5 km.

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50*3= 47.5*Pm

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Thus with an average density of 2.8gram per centimeter cube

50*2.8= (50-x)*3.16

(50-x)= (50*2.8)/3.16

50-x=44.3

x=50-44.3= 5.7

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the density of a steel is 7.8.find the mass of steel cube of side 10 cm. find volume of steel if the mass is 8kg​
lukranit [14]

Answer:

Mass of the steel cube =  7800 kg

Volume of the steel  = 1.025 cubic centimetre

Explanation:

Given:

The density of the steel   =  7.8

Side of the cube = 12 cm

<u>(1)The mass of steel cube :</u>

We know that,

Density  = \frac{Mass}{Volume}

We are given with density and sides of the cube

then volume of the cube

= (side)^3

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Now

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mass = 7.8 \times 1000

mass =  7800 kg

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Given the mass  = 8 kg

Density  = \frac{Mass}{Volume}

Substituting the values

7.8 = \frac{8}{volume}

volume = \frac{8}{7.8}

volume = 1.025 cubic centimetre

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