Question

A satellite orbits the earth a distance of above the planet’s surface and takes 6.43 hours for each revolution about the earth. The earth’s radius is 6.38 × 106 m. The acceleration of this satellite is closest to

Answer 1

Answer:

Explanation:

Time period of satellite T = 6.43 X 60 X 60 s

acceleration = ω²R

4π²x R / T²

4 x 3.14²x 6.38 x 10⁶ / (6.43 x60 x 60)²

= 0.47 m /s²