Answer:
The answer is 1. A type of acid that completely reacts with water.
Explanation:
A strong acid dissociates completely in water to release hydrogen ions as the only positive ions.
This is the simple definition of Arrhenius acid.
Answer:
C. 0.191 M
Explanation:
Our goal for this question, is to calculate the concentration of the HCl solution. For this, in the experiment, a solution of NaOH was used to find the moles of HCl. Therefore, our first step is to know the <u>reaction between HCl and NaOH</u>:

The "<u>titrant"</u> in this case is the NaOH solution. If we know the concentration of NaOH (0.100M) and the volume of NaOH (38.2 mL=0.0382 L), we can calculate the moles using the <u>molarity equation</u>:



Now, in the reaction, we have a <u>1:1 molar ratio</u> between HCl and NaOH (1 mol of HCl is consumed for each mole of NaOH added). Therefore we will have the same amount of moles of HCl in the solution:

If we want to calculate the molarity of the HCl solution we have to <u>divide by the litters</u> of HCl used in the experiment (20 mL= 0.02 L):

The concentration of the HCl solution is 0.191 M
I hope it helps!
Explanation:
It is given that the initial mass of benznene is 7.9286 g
Mass of benzene left = 5.9987 g
So, mass of benzene with which gas get saturated will be calculated as follows.
= 7.9286 g - 5.9987 g = 1.9299 g
Therefore, moles of benzene with which gas get saturated =
=
= 0.0247 moles
Temperature =
= 27.3 + 273.15 = 300.45 K
Volume = 5.01 L
So, according to ideal gas equation PV = nRT
Putting the given values into the ideal gas equation as follows.
PV = nRT
= 
P = 
= 92.371 torr
Hence, we can conclude that vapor pressure of benzene is 92.371 torr.
Answer:
An emission spectrum.
Explanation:
An element's emission spectrum is the intensity of the electromagnetic radiation of each frequency emitted by the atoms of that element during excitation. In the case of sodium vapor, when the vapor is excited by an applied voltage or an electric force or field, the atoms in the vapor emits a light spectrum.