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Allushta [10]
3 years ago
5

At which temperature would a can of soda be most fizzy when it is opened? 30°C 40°C 20°C 10°C

Chemistry
2 answers:
scoray [572]3 years ago
5 0

I think the answer is 40⁰C

I hope this helps you!

Helga [31]3 years ago
4 0

The answer to your question is 40° because freezing temp for a liquid is 32°

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Please match the following acids with its description:
marin [14]

Answer:

The answer is 1. A type of acid that completely reacts with water.

Explanation:

A strong acid dissociates completely in water to release hydrogen ions as the only positive ions.

This is the simple definition of Arrhenius acid.  

3 0
3 years ago
4. A 0.100 M solution of NaOH is used to titrate an HCl solution of unknown concentration. To neutralize the solution, an averag
PtichkaEL [24]

Answer:

C. 0.191 M

Explanation:

Our goal for this question, is to calculate the concentration of the HCl solution. For this, in the experiment, a solution of NaOH was used to find the moles of HCl. Therefore, our first step is to know the <u>reaction between HCl and NaOH</u>:

HCl~+~NaOH~->~NaCl~+~H_2O

The "<u>titrant"</u> in this case is the NaOH solution. If we know the concentration of NaOH (0.100M) and the volume of NaOH (38.2 mL=0.0382 L), we can calculate the moles using the <u>molarity equation</u>:

M=\frac{mol}{L}

0.100~M=\frac{mol}{0.0382~L}

mol=0.100~M*0.0382~L=0.0382~mol~of~NaOH

Now, in the reaction, we have a <u>1:1 molar ratio</u> between HCl and NaOH (1 mol of HCl is consumed for each mole of NaOH added). Therefore we will have the same amount of moles of HCl in the solution:

0.0382~mol~of~NaOH\frac{1~mol~HCl}{1~mol~NaOH}=0.0382~mol~HCl

If we want to calculate the molarity of the HCl solution we have to <u>divide by the litters</u> of HCl used in the experiment (20 mL= 0.02 L):

\frac{0.0382~mol~HCl}{0.02~L}~=~0.191~M

The concentration of the HCl solution is 0.191 M

I hope it helps!

8 0
3 years ago
Which substance is an electrolyte? 1. O2 2. Xe 3. C3H8 4. KNO3
Troyanec [42]
KNO3 is an electrolyte
3 0
3 years ago
.The vapor pressure of a volatile liquid can be determined by slowly bubbling a known volume of gas through it at a known temper
Elis [28]

Explanation:

It is given that the initial mass of benznene is 7.9286 g

Mass of benzene left = 5.9987 g

So, mass of benzene with which gas get saturated will be calculated as follows.

               = 7.9286 g  - 5.9987 g  = 1.9299 g

Therefore, moles of benzene with which gas get saturated = \frac{mass}{ molar mass}

                = \frac{1.9299 g}{78.112 g/mol}

                = 0.0247 moles

Temperature = 27.3^{o}C = 27.3 + 273.15 = 300.45 K

Volume = 5.01 L

So, according to ideal gas equation PV = nRT

Putting the given values into the ideal gas equation as follows.

                       PV = nRT

           P \times 5.01 L = 0.0247 mol \times 62.36 torr-liter/mol K \times 300.45 K

                   P = \frac{462.781 torr-liter}{5.01 L}

                      = 92.371 torr

Hence, we can conclude that vapor pressure of benzene is 92.371 torr.

8 0
3 years ago
3. The light given off by an electric discharge through sodium vapor is
Fittoniya [83]

Answer:

An emission spectrum.

Explanation:

An element's emission spectrum is the intensity of the electromagnetic radiation of each frequency emitted by the atoms of that element during excitation. In the case of sodium vapor, when the vapor is excited by an applied voltage or an electric force or field, the atoms in the vapor  emits a  light spectrum.

6 0
4 years ago
Read 2 more answers
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