What is meant by the term "observable universe"
1 answer:
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Answer:
The velocity of the shell when the cannon is unbolted is 500.14 m/s
Explanation:
Given;
mass of cannon, m₁ = 6430 kg
mass of shell, m₂ = 73.8-kg
initial velocity of the shell, u₂ = 503 m/s
Initial kinetic energy of the shell; when the cannon is rigidly bolted to the earth.
K.E = ¹/₂mv²
K.E = ¹/₂ (73.8)(503)²
K.E = 9336032.1 J
When the cannon is unbolted from the earth, we apply the principle of conservation of linear momentum and kinetic energy
change in initial momentum = change in momentum after
0 = m₁u₁ - m₂u₂
m₁v₁ = m₂v₂
where;
v₁ is the final velocity of cannon
v₂ is the final velocity of shell
Apply the principle of conservation kinetic energy
Therefore, the velocity of the shell when the cannon is unbolted is 500.14 m/s
Answer:
Explanation:
here we know that car starts from rest and continue to accelerate till it will reach to maximum speed of 20 m/s
so we will have
so car will accelerate till t = 10 then it will move with uniform speed
so the distance moved by the car till it accelerates is given as
now it will move with uniform speed for next 36 s
so we have
so total distance moved by the car is given as