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tigry1 [53]
3 years ago
12

You do work on something when you lift if against gravity. Explain how work relates to gravitational potential energy using at l

east two complete content related sentences. If the lifted object is released, describe the change in energy. Be sure to define all terms used in both questions.
Physics
1 answer:
stellarik [79]3 years ago
4 0
1) Work on something when you lift it against gravity

The work is the change in mechanical energy. Assuming the velocity is constant the kinetic energy does not change, and the change in mechanical energy is the change in potential energy.

Mathematically:

Work on the object = final potential energy - initial potential energy = m*g*H2 - m*g*H1 = m*g*ΔH.

2) Change in energy when the lifted object is released.

In this case, the object losses potential energy as it goes down and gains kynetic energy as the object gains speed. So, the energy is conserved along all the motion up to the object gets the ground, when all the energy is transformed into heat and sound.
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PLEASE ANSWER ASAP I REALLY NEED HELP!!!!!!
Andrews [41]

Answer:

In thermodynamics, heat is transferred energy that moves between substances or systems because of their temperature difference. According to the first law of thermodynamic and the law of energy conversion s a form of energy, heat is cannot be created or destroyed only moves from one form to other.

The stone gets heat energy from fire and moves this heat energy or thermal energy to water as it cools off and the water warms up. Heat moves or is transferred spontaneously from the hot stone into the cold water. Eventually, the stone and water have the same temperature and water becomes heated. At the time of heat flowing out of the stone into the water, the heat energy became less ordered, due to spreading out through both the stone and the water. This is a net increase in entropy which is the second law of entropy.

4 0
3 years ago
A 90. 0-kg ice hockey player hits a 0. 150-kg puck, giving the puck a velocity of 45. 0 m/s. If both are initially at rest and i
Mice21 [21]

The distance traveled by the hockey player is 0.025 m.

<h3>The principle of conservation of linear momentum;</h3>
  • The principle of conservation of linear momentum states that, the total momentum of an isolated system is always conserved.

The final velocity of the hockey play is calculated by applying the principle of conservation of linear momentum;

m_1v_1 = m_2 v_2\\\\v_1 = \frac{m_2 v_2}{m_1} \\\\v_1 = \frac{0.150 \times 45}{90} \\\\v_1 = 0.075 \ m/s

The time taken for the puck to reach 15 m is calculated as follows;

t = \frac{d}{v} \\\\t = \frac{15\ m}{45 \ m/s} \\\\t = 0.33 \ s

The distance traveled by the hockey player at the calculated time is;

d = vt\\\\d = 0.075 \ m/s \ \times 0.33 \ s\\\\d = 0.025 \ m

Learn more about conservation of linear momentum here: brainly.com/question/7538238

4 0
2 years ago
How long must a tow truck apply a force of 600 N to increase the speed of a 1,500 kg car at rest to 2 m/s?
slega [8]

The time the truck must apply the given force to increase its speed to given value is 5 s.

The given parameters;

  • <em>applied force, F = 600 N</em>
  • <em>mass of the truck, m = 1,500 kg</em>
  • <em>speed of the truck, v = 2 m/s</em>

The force applied to the truck is determined by Newton's second law of motion; <em>which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.</em>

F = ma

F = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{1500 \times 2}{600} \\\\t = 5 \ s

Thus, the time the truck must apply the given force to increase its speed to given value is 5 s.

Learn more here:brainly.com/question/1988795

7 0
3 years ago
Why do planets rings surround them and not the sun
Shalnov [3]

Well, the rings surrounding a planet are made out of rock. A ring surrounding the sun would be impossible since the sun can reach more than 27 million degrees Fahrenheit (15 million degrees Celsius.)

Hope this helped.

7 0
4 years ago
Please help me anyone i will mark brainliest
Mashcka [7]

Answer:

for 4.567 I can't tell if it x 10^{3} or x 10^{5} so:

answer using x 10^{3} = 0.0000644697N

answer using x 10^{5} = 0.00644697

Explanation:

use equation F = GMm/R^{2}

3 0
3 years ago
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