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tekilochka [14]
2 years ago
7

Please help me anyone i will mark brainliest

Physics
1 answer:
Mashcka [7]2 years ago
3 0

Answer:

for 4.567 I can't tell if it x 10^{3} or x 10^{5} so:

answer using x 10^{3} = 0.0000644697N

answer using x 10^{5} = 0.00644697

Explanation:

use equation F = GMm/R^{2}

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3 years ago
(a) Calculate the rate of heat conduction through house walls that are 13.0 cm thick and that have an average thermal conductivi
Mkey [24]

Answer:

a. 960 W b. One 1 kW room heater

Explanation:

a. The rate of heat conduction P = kA(T₂ - T₁)/d where k = 2 × 0.040 W/m-K =  0.080 W/m-K since the thermal conductivity of glass wool is 0.040 W/m-K and that of the material is twice the thermal conductivity of glass wool, A = area of walls = 120 m², T₁ = outside surface temperature = 5.0 °C, T₂ = inside surface temperature = 18.0 °C and d = thickness of wall = 13.0 cm = 0.13 m

P = kA(T₂ - T₁)/d

= 0.080 W/m-K × 120 m²(18.0 °C - 5.0 °C)/0.13 m

= 9.6 Wm/K × 13 K/0.13 m

= 124.8 Wm/0.13 m

= 960 W

b. The number of 1 kW room heater required will be

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So we need only one 1 kW room heater.

6 0
4 years ago
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