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Nataly_w [17]
2 years ago
12

What type of electromagnetic wave has a frequency of around 1012 Hz?​

Physics
2 answers:
amm18122 years ago
4 0
Microwave frequencies range from about 109 Hz to the highest practical LC resonance at nearly 1012 Hz. Since they have high frequencies, their wavelengths are short compared with those of other radio waves—hence the name “microwave.” Microwaves can also be produced by atoms and molecules.

Pls Mark Brainliest if correct.
devlian [24]2 years ago
3 0

Answer: Hello, here is somthing that might help. Microwave frequencies range from about 109 Hz to the highest practical LC resonance at nearly 1012 Hz. Since they have high frequencies, their wavelengths are short compared with those of other radio waves—hence the name “microwave.” Microwaves can also be produced by atoms and molecules.

Explanation: Tell me if this helps o not :)

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Compute your average velocity in the following two cases: (a) You walk 50.2 m at a speed of 2.21 m/s and then run 50.2 m at a sp
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Answer:

a) 2.87 m/s

b) 3.23 m/s

Explanation:

The avergare velocity can be found dividing the length traveled d by the total time t.

a)

For the first part we easily know the total traveled length which is:

d = 50.2 m + 50.2 m = 100.4 m

The time can be found dividing the distance by the velocity:

t1 = 50.2 m / 2.21 m/s = 22.7149 s

t2 = 50.2 m / 4.11 m/s = 12.2141 s

t = t1 +t2 = 34.9290 s

Therefore, the average velocity is:

v = d/t =2.87 m/s

b)

Here we can easily know the total time:

t = 1 min + 1.16 min = 129.6 s

Now the distance wil be found multiplying each velocity by the time it has travelled:

d1 = 2.21 m/s * 60 s = 132.6 m

d2 = 4.11 m/s *(1.16 * 60 s) = 286.056 m

d = 418.656 m

Therefore, the average velocity is:

v = d/t =3.23 m/s

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A star that is several thousand dimmer than the sun with a temperature than 10000 k would be classified as
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Select the correct answer.
skelet666 [1.2K]

Answer:

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A 40-cmcm-long tube has a 40-cmcm-long insert that can be pulled in and out. A vibrating tuning fork is held next to the tube. A
Licemer1 [7]

Answer:

1070 Hz

Explanation:

First, I should point out there might be a typo in the question or the question has inconsistent values. If the tube is 40 cm long, standing waves cannot be produced at 42.5 cm and 58.5 cm lengths. I assume the length is more than the value in the question then. Under this assumption, we proceed as below:

The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength \frac{\lambda}{2}.

Hence, we have

\dfrac{\lambda}{2}=58.5-42.5=16 \text{ cm}

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v=f\lambda

f=\dfrac{v}{\lambda}

f=\dfrac{343}{0.32}=1070 \text{ Hz}

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3 years ago
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