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Travka [436]
3 years ago
8

Which group iia metal magnesium or calcium is more active cite your evidence?

Chemistry
1 answer:
Burka [1]3 years ago
5 0
Calcium is more active because it is under magnesium on periodic table.
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Iodine-131 decays with a half-life of 8.02
dlinn [17]
Radioactive material undergoes 1st order decay kinetics.

For 1st order decay, half life = 0.693/k

where k = rate constant

k = 0.693/half life = 0.693/8.02 = 0.0864 day-1

Now, for 1st order reaction,
k = \frac{2.303}{t} X log \frac{initial.conc}{final.conc}

Given: t = 6.01d, initial conc. = 5mg

∴0.0864 = \frac{2.303}{6.01} X log \frac{5}{final.conc}
∴ final conc. = 2.975 mg
3 0
3 years ago
If an ideal gas has a pressure of 5.49 atm, a temperature of 88.78 °c, and has a volume of 22.03 l, how many moles of gas are in
kirza4 [7]
N = (PV)/RT
(T = 88.78 + 273 = 361.78K)
(R = 22.4/273 = 0.082)
= (5.49 x 22.03)/(0.082 x 361.78) = ?
Put it into the calculator. It's hard to do that on a mobile phone.
7 0
4 years ago
Which term describes this reactions?
Salsk061 [2.6K]

Answer:

Elimination

Explanation:

Since they are removing water from the solution, it is called elimination.

5 0
3 years ago
Read 2 more answers
What is the theoretical yield of SO3 produced by 8.96 g of S?
Virty [35]

Answer: Theoretical yield of SO_3 produced by 8.96 g of S is 33.6 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}

\text{Moles of} S=\frac{8.96g}{32g/mol}=0.28moles

The balanced chemical equation is:  

2S+3O_2\rightarrow 2SO_3  

According to stoichiometry :

2 moles of S produce =  3 moles of SO_3

Thus 0.28 moles of S will produce=\frac{3}{2}\times 0.28=0.42moles  of SO_3  

Mass of SO_3=moles\times {\text {Molar mass}}=0.42moles\times 80g/mol=33.6g

Thus theoretical yield of SO_3 produced by 8.96 g of S is 33.6 g

7 0
3 years ago
PLZ HELP
shusha [124]
Use the equation for density :
Density = mass / volume
Density = 120 / 480
Density = 0.25

5 0
3 years ago
Read 2 more answers
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