Calculate first the number of moles of ethylene glycol by dividing the mass by the molar mass.
n = (6.21 g ethylene glycol) / 62.1 g/mol
n = 0.1 mol
Then, calculate the molality by dividing the number of moles by the mass of water (in kg).
m = 0.1 mol/ (0.025 kg) = 4m
Then, use the equation,
Tb,f = Tb,i + (kb)(m)
Substituting the known values,
Tb,f = 100°C + (0.512°C.kg/mol)(4 mol/kg)
<em>Tb,f = 102.048°C</em>
Answer:
Where is the diagram?please put the pictu
Answer:
a nitrogen containing base, a pentose (five-carbon) sugar, and one or more phosphate groups
Explanation:
found this information on, newworldencyclopedia.com
The answer is 315.59095 grams :)
I think it would be 2,510 kJ, or 2,510,000 J.
