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3 years ago

A blank is 2 or more substances that are together in the same place but are not chemically combined.

1 answer:

7 0

A mixture is a material system made up of two or more different substances, which are mixed but not combined chemically. A mixture refers to the physical combination of two or more substances in which the identities of the individual substances are retained.

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Can someone answer this for me and show proof I WILL MARK BRAINLIEST

AlexFokin [52]

Answer:

Explanation:

Caus it makes sense

7 0

3 years ago

A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.

Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

$[SCN^-]=0.00012 mol/L$

The analytical concentrations of ferric ions:

$[Fe^{3+}]=0.063 mol/L$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

1) Moles of sodium thiocyanate = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = $4.8\times 10^{-4} M$

$n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol$

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in $2.4\times 10^{-6}mol$ of NaSCN.

$=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol$

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

$n'=0.002 M\times 0.21 L=0.00042 mol$

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

$3\times 0.00042 mol=0.00126 mol$

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

$[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L$

The analytical concentrations of ferric ions:

$[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L$

3 0

3 years ago

Read 2 more answers

PLEASE HELP

swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

5 0

4 years ago

All of the following are conductors of electricity except

butalik [34]

What are the choices?

7 0

4 years ago

What is the best chemical test for alkene?

enyata [817]

Answer:

bromine water

Explanation:

a simple test with bromine water can be used to tell the difference between an alkane and an alkene. an alkene will turn brown bromine water colourless as the bromine reacts with the carbon-carbon double bond.

3 0

4 years ago