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Firdavs [7]
3 years ago
15

In the equation: 23491Pa → 234 92U + X The X represents a

Chemistry
1 answer:
Bad White [126]3 years ago
3 0
Beta particle in the reaction
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Which characteristic is found in liquids and gases? A. Has a fixed volume B. Particles stay in a fixed position C. No particle m
STALIN [3.7K]

Answer:

The answer to your question is letter D.

Explanation:

A. Has a fixed volume This is not the right answer, liquids and gases take the shape of the container in which they are.

B. Particles stay in a fixed position This answer is wrong, this characteristic is  of solids but not of liquids and gases.

C. No particle movement This characteristic is also of solids, in liquids and gases the particles can move.

D. Takes the shape of the container. This is the right answer, liquids and gases take the shape of the container.

6 0
3 years ago
Read 2 more answers
1 lb of CO2 occupies 0.6 ft^3 at a pressure of 200 psi. Determine the temperature of the system.
Anarel [89]

<u>Answer:</u> The temperature of the system is 273 K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of carbon dioxide = 1 lb = 453.6 g   (Conversion factor: 1 lb = 453.6 g)

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

\text{Moles of carbon dioxide}=\frac{453.6g}{44g/mol}=10.31mol

To calculate the temperature of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of carbon dioxide = 200 psia = 13.6 atm   (Conversion factor:  1 psia = 0.068 atm)

V = Volume of carbon dioxide = 0.6ft^3=16.992L    (Conversion factor:  1ft^3=28.32L )

n = number of moles of carbon dioxide = 10.31 mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the system = ?

Putting values in above equation, we get:

13.6atm\times 16.992L=10.31mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times T\\\\T=273K

Hence, the temperature of the system is 273 K

8 0
3 years ago
Question 3 of 10
PIT_PIT [208]

Answer:

the moluculer formula is the answer

Explanation:

4 0
3 years ago
What is the theoretical yield of aluminum oxide if 1.40 mol of aluminum metal is exposed to 1.35 mol of oxygen?
jasenka [17]

Answer:

71.372 g or 0.7 moles

Explanation:

We are given;

  • Moles of Aluminium is 1.40 mol
  • Moles of Oxygen 1.35 mol

We are required to determine the theoretical yield of Aluminium oxide

The equation for the reaction between Aluminium and Oxygen is given by;

4Al(s) + 3O₂(g) → 2Al₂O₃(s)

From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.

Therefore;

1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen

1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium

Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.

4 moles of aluminium reacts to generate 2 moles aluminium oxide.

Therefore;

Mole ratio Al : Al₂O₃ is 4 : 2

Thus;

Moles of Al₂O₃ = Moles of Al × 0.5

                         = 1.4 moles × 0.5

                         = 0.7 moles

But; 1 mole of Al₂O₃ = 101.96 g/mol

Thus;

Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol

                                            = 71.372 g

3 0
3 years ago
Naming chlorine as an Ion
Katarina [22]

The name of the ion is chloride.

To name a <em>monatomic anion</em>

• <em>Drop the ending</em> of the element name (chlor<u>ine</u> → chlor)

• <em>Add the ending</em> <em>ide</em> (chlor + ide → chloride)

4 0
3 years ago
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