14 electrons because there are 7 orbitals (2x7=14)
Answer:
option C.there is an accumulation of carbon dioxide.
Explanation:
Answer:
Explanation:
We're given the following ions:
Hydrogen sulfide is a weak acid, so it only ionizes to ions to a very low extent. This means we would expect to see it in a molecular form in a net ionic equation rather than a dissociated form (hydrogen cations and sulfide anions). In each of these net ionic equations, we expect the three cations to displace hydrogen from hydrogen sulfide and form three precipitates.
Firstly, iron(II) displaces hydrogen forming iron(II) sulfide and acidic conditions:
Secondly, chromium(III) cation displaces hydrogen forming chromium(III) sulfide:
Thirdly, nickel(II) cation displaces hydrogen forming nickel sulfide:
<h3>
Answer:</h3>
126.14 g
<h3>
Explanation:</h3>
- Complete combustion of hydrocarbons yields water and carbon dioxide.
- Methane is a hydrocarbon in the homologous series known as alkanes.
- Methane undergoes combustion in air to produce water and carbon dioxide according to the equation below.
CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)
<u>We are given;</u>
We are required to determine the mass of H₂O produced
<h3>Step 1: Moles of H₂O produced</h3>
- From the equation 1 mole of methane undergoes combustion to produce 2 mole of H₂O.
Therefore, Moles of methane = Moles of H₂O × 2
Hence, Moles of H₂O = 7.0 moles
<h3>Step 2: Mass of H₂O produced </h3>
We know that; mass = Moles × Molar mass
Molar mass of water = 18.02 g/mol
Therefore;
Mass of water = 7.0 moles × 18.02 g/mol
= 126.14 g
Thus, the mass of water produced is 126.14 g
You need to use the formula--> P1V1= P2V2 (Boyles's law)
P1= 14 bar
V1= 312 mL
P2= ?
V2= 652 mL
now we plug the values into the formula.
(14 x 312) = (P2x 652)
P2= (14 x 312)/ 652= <span>6.70 bar</span>
