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jeka57 [31]
3 years ago
10

In chemistry class, a student conducted an investigation on the factors that affect the solubility of copper (II) sulfate (CUSO)

in water. The data were recorded in the following table.

Chemistry
1 answer:
beks73 [17]3 years ago
3 0

Answer:

See Explanation

Explanation:

The rate of a chemical reaction depends on certain factors. Some of these factors include; surface area, temperature, nature of reactants etc.

The trial that exhibits the slowest rate of dissolution of CuSO4 crystals is trial 2 because the crystals have a small surface area since the crystals were large. Also, the solution was not agitated or stirred to increase the rate of collision between the water and the CuSO4 crystals.

Increase in temperature, agitation of the reaction solution and high surface area increases the rate of collision between the water and CuSO4 crystals leading to a faster rate of dissolution. This occurs in trial 3.

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What volume (mL) of the sweetened tea described in Example 1 contains the same amount of sugar (mol) as 10 mL of the soft drink
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The question is incomplete, the complete question is:

What volume (mL) of the sweetened tea described in Example 3.14 contains the same amount of sugar (mol) as 10 mL of the soft drink in this example. The example is attached below.

<u>Answer:</u> 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

<u>Explanation:</u>

We first calculate the number of moles of soft drink in a volume of 10 mL

The formula used to calculate molarity:

\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}} .....(1)

Taking the concentration of soft drink from the example be = 0.375 M

Volume of solution = 10 mL

Putting values in equation 1, we get:

0.375=\frac{\text{Moles of sugar in soft drink}\times 1000}{10}\\\\\text{Moles of sugar in soft drink}=\frac{0.375\times 10}{1000}=0.00375mol

<u>Calculating volume of sweetened tea:</u>

Moles of sugar = 0.00375 mol

Molarity of sweetened tea = 0.05 M

Putting values in equation 1, we get:

0.05=\frac{0.00375\times 1000}{\text{Volume of sweetened tea}}\\\\\text{Volume of sweetened tea}=\frac{0.00375\times 1000}{0.05}=75mL

Hence, 75 mL of sweetened tea will contain the same amount of sugar as in 10 mL of soft drink

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In a classical long run supply model the economy is always doing what
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Answer:

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The reactants have one C atom and four O and H atoms. Hope this helps :)
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Answer:

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First we <u>convert 36.12 g of AI₂O₃ into moles</u>, using its <em>molar mass</em>:

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Then we <u>convert AI₂O₃ moles into O₂ moles</u>, using the stoichiometric coefficients of the reaction:

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We can now use the <em>PV=nRT equation</em> to <u>calculate the volume</u>, V:

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