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andrew11 [14]
3 years ago
6

Which of the following statements is true about the role of oxygen in cellular respiration? It reacts with water. It is one of t

he ending compounds. It is one of the beginning compounds. It reacts with carbon dioxide.
Chemistry
2 answers:
skad [1K]3 years ago
6 0

"It reacts with water" is incorrect I took the test and got it wrong. I believe it is B, because oxygen combines with glucose and makes carbon dioxide.

Daniel [21]3 years ago
4 0

cellular respiration the starting compounds are glucose and oxygen and the ending compounds are carbon dioxide, water, and energy.

C6H12O6+6O2-->6CO2+6H2O+ energy

Glucose (sugar)+oxygen--> Carbon Dioxide+ water+energy

so It is one of the starting compounds

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The following statement is True.

8 0
3 years ago
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When cells are dividing, it is
DiKsa [7]

Answer:

Chromosome is basically made of DNA and proteins.

Explanation:

Chromosomes contain thread like structure present inside the nucleus of the cell.Chromosome is generally made of DNA and proteins(Histone proteins).

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    The  wrapping of DNA around the histone proteins helps in the formation of nucleosome which helps in the packing of DNA inside the chromosome.

8 0
3 years ago
You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the
Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

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= 25.35%

8 0
2 years ago
How many chlorine ions are required to bond with one aluminum ion and why??
antiseptic1488 [7]
3 Chlorine ions are required to bond with one aluminum ion.

In ionic bonds, metals atoms loses all its outermost shell electrons to form a cation. While, non metal atoms gains however many electrons in order to make its outermost electron shell be 8 (or 2 if there's only one shell).

Therefore, form the periodic table, we can see that aluminum has a atomic number of 13, which makes its electron arrangement be 2,8,3. So, in order to form a aluminum ion, an Al atom must lose 3 electrons. On the other hand, Chlorine has a atomic number of 17, which means it has the electron configuration of 2,8,7. It has to gain only 1 electron to have 8 outermost shell electron.

Thereofre, 3 Chlorine atom are required to gain all 3 electrons given out by just 1 aluminum ion.
8 0
3 years ago
What volume of 6.58M HCI is needed to make 500. mL of 3.00M HCI?
zmey [24]

Answer:

228 mL

Explanation:

M1*V1 = M2*V2

M1 = 6.58 M

V1 = ?

M2 = 3.00 M

V2 = 500 mL

V1 = M2*V2/M1 = 3.00M*500.mL/6.58 M = 228 mL

3 0
3 years ago
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