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Basile [38]
3 years ago
9

Is this statement true or false? Living things are classified by shared characteristics.

Chemistry
1 answer:
RoseWind [281]3 years ago
8 0

Answer:

True!

Explanation:

Living things are classified by the characteristics they have in common. All living organisms are classified within the organization based on extremely fundamental, shared characteristics.

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List three ways that energy could be lost between water and food
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5 0
1 year ago
You need to prepare 100.0 mL of a pH 4.00 buffer solution using 0.100 M benzoic acid (p K a = 4.20 ) and 0.200 M sodium benzoate
bekas [8.4K]

Answer : The volume of sodium benzoate and benzoic acid  solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.

Explanation :

Let the volume of sodium benzoate (salt) be, x

So, the volume of benzoic acid  (acid) will be, (100 - x)

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

Now put all the given values in this expression, we get:

4.00=4.20+\log \left(\frac{(\frac{0.200x}{100})}{(\frac{0.100(100-x)}{100})}\right)

x = 29.0

The volume of sodium benzoate = x = 29.0 mL

The volume of benzoic acid  (acid) = (100 - x) = (100 - 29.0) = 71 mL

Thus, the volume of sodium benzoate and benzoic acid  solution mixed to prepare this buffer should be, 29.0 mL and 71 mL respectively.

5 0
3 years ago
Are these correct? Also, what is number 7?
crimeas [40]
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4 0
3 years ago
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A sample of ideal gas at room temperature occupies a volume of 12.0 L at a pressure of 802 torr . If the pressure changes to 401
Blababa [14]

 The new  volume  is  2.4 L

<u><em> calculation</em></u>

The new volume is calculated using Boyle's  law formula

That  is  P₁V₁=P₂V₂

where,

p₁ =  802 torr

V₁ = 12.0 l

P₂ = 4010 torr

V₂=?

make  V₂ the subject of the formula  by diving  both side of equation by P₂

V₂ = P₁V₁/P₂

V₂  is therefore = {(12.0 l × 802 torr) 4010 torr}  = 2.4 L


7 0
3 years ago
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