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posledela
2 years ago
9

Describe how different environments support different varieties of organisms

Chemistry
1 answer:
vladimir2022 [97]2 years ago
3 0

Answer:

How is an environment able to support different varieties of organisms? ... It provides all the necessary conditions, such as temperature, space, water and food resources, oxygen and carbon dioxide, that suit the needs of the organisms. Examples of habitat include forests, mountains, bodies of water, and even puddles.

Explanation:

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sergeinik [125]

Answer: chromosome

Explanation: :)

4 0
3 years ago
Read 2 more answers
Which phrases describe clastic sedimentary rocks? Check all that apply.
Romashka [77]

Explanation:

A clastic sedimentary rock is a rock that is formed from pre-existing rock materials and minerals. This materials have been transported to their new positions by the agents of denudation.

  1. Clastic sedimentary rocks are made up of rock fragments predominantly.
  2. The matrix is usually remnants of other rocks.
  3. A cementing material can form between clasts and holds them in place. Cements are usually iron oxides, calcite e.t.c.
  4. These rock types are usually formed from mechanincal weathering of rocks
  5. Mechanical weathering breaks down rocks into chunks.
  6. Examples are breccia, conglomerates, e.t.c.

Learn more:

Sedimentary rocks brainly.com/question/2740663

#learnwithBrainly

5 0
3 years ago
If a gas occupies a volume of 6.6 L at 16.0 °C, at what temperature, in °C, will it occupy a volume of 8.9 L if the pressure rem
Pachacha [2.7K]

Answer:

ok

Explanation:

5 0
3 years ago
Determine how many millilitres of a 4.25 M HCl solution are needed to react completely with 8.75 g CaCO3?
Helen [10]

Answer:

41 mL

Explanation:

Given data:

Milliliter of HCl required = ?

Molarity of HCl solution = 4.25 M

Mass of CaCO₃ = 8.75 g

Solution:

Chemical equation:

2HCl + CaCO₃      →    CaCl₂ + CO₂ + H₂O

Number of moles of CaCO₃:

Number of moles = mass/molar mass

Number of moles = 8.75 g / 100.1 g/mol

Number of moles = 0.087 g /mol

Now we will compare the moles of  CaCO₃ with HCl.

                      CaCO₃         :          HCl

                          1               :            2

                      0.087           :         2/1×0.087 = 0.174 mol

Volume of HCl:

Molarity = number of moles / volume in L

4.25 M = 0.174 mol / volume in L

Volume in L = 0.174 mol /4.25 M

Volume in L = 0.041 L

Volume in mL:

0.041 L×1000 mL/ 1L

41 mL

8 0
2 years ago
Please help me out!!!
patriot [66]

Answer:

Use a scientific calculator

4 0
2 years ago
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