High Pitch sounds have relativity large frequency and small wavelength
A surfer is riding a wave with an amplitude of 6 feet and a period of 24 feet. If the wave completes a period in 8 seconds.The speed of the surfer is 3ft/sec.
A wave's amplitude is defined as its largest displacement on either side of its mean location.
The quantity of oscillations a wave makes in a second is referred to as frequency of wave.
The amount of time it takes to complete one vibration, from A to B, is referred to as time period.
As we know,
ν = λf
where, ν = speed
λ = wavelength
f = frequency
also,
Putting in the values in equation ν = λf gives us,
ν = 24 × ( period of wave must means wavelength of 24ft)
ν = 3ft/sec.
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Answer:
Displacement method of volume measurement is no suitable
Explanation:
Displacement method of volume measurement is no suitable for the objects that do not get immersed into the water completely because of the hindrance in accuracy of the measurement.
Answer:
f = 5.3 Hz
Explanation:
To solve this problem, let's find the equation that describes the process, using Newton's second law
∑ F = ma
where the acceleration is
a =
B- W = m \frac{d^2 y}{dt^2 }
To solve this problem we create a change in the reference system, we place the zero at the equilibrium point
B = W
In this frame of reference, the variable y' when it is oscillating is positive and negative, therefore Newton's equation remains
B’= m
the thrust is given by the Archimedes relation
B = ρ_liquid g V_liquid
the volume is
V = π r² y'
we substitute
- ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }
this differential equation has a solution of type
y = A cos (wt + Ф)
where
w² = ρ_liquid g π r² /m
angular velocity and frequency are related
w = 2π f
we substitute
4π² f² = ρ_liquid g π r² / m
f =
calculate
f =
f = 5.3 Hz