Answer:
The number of turns in the solenoid is 22366.
Explanation:
The number of turns in the solenoid can be found using the following equation:
Where:
B: is the magnetic field = 8.90 T
L: is the solenoid's length = 0.300 m
N: is the number of turns =?
I: is the current = 95 A
μ₀: is the magnetic constant = 4π×10⁻⁷ H/m
By solving equation (1) for N we have:
Therefore, the number of turns in the solenoid is 22366.
I hope it helps you!
Answer: 
Explanation:
Given
Length of beam 
mass of beam 
Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude
Also, the beam starts rotating about its center
So, the moment of inertia of the beam is
Torque is the product of moment of inertia and angular acceleration
<u>Answer</u>
48 Volts
<u>Explanation</u>
The question can be solve using the turn rule of a transformer that states;
Np/Ns = Vp/Vs
Where Np ⇒ number of turns in the primary coil.
Ns ⇒number of turns in the seconndary coil
Vp ⇒ primary voltage
Vs ⇒secondary voltage
Np/Ns = Vp/Vs
10/4 = 120/Vp
Vp = (120 × 4)/10
= 480/10
= 48 Volts
-- If 2,000 newtons of force were applied through a distance of 1,000 meters,
then 2,000,000 newton-meters = 2,000,000 joules of work were done.
-- 45 minutes = (45 x 60) = 2,700 seconds
-- Power = (work) / (time) = (2,000,000 j) / (2,700 s) = <u>740.74 watts</u>
Interestingly, that's almost exactly 1 horsepower. (0.99295... of 746 watts)
