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3 years ago

Why do gasses condense when cooled

Chemistry

1 answer:

Darya [45]3 years ago

6 0

Gassed condense because molecules decrease inside

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What mass of cu(s)cu(s) is electroplated by running 14. 5 aa of current through a cu2 (aq)cu2 (aq) solution for 4. 00 hh?

galina1969 [7]

The mass of Copper electroplated is 68.76 g

<h3>What is electroplating?</h3>

The process of plating a metal onto another is known as electroplating.

It is often used to prevent corrosion of metal or for the decorative purposes

In this process, electric current is passed through an aqueous solution containing dissolved cations.

The dissolved cations are reduced developing a thin metal coating on the electrode.

At cathode,

$Cu^{2+}(aq) + 2e^-\rightarrow Cu(s)$

Current, I = 14.5 A

Time, t = 4 hrs = 4×60×60 = 14400 sec

Charge, q = It = 14.5×14400= 208800 C

Copper metal deposited by 2×96487 C = 63.55 g

Copper metal deposited by 208800 C = $\frac{63.55 \times208800}{2\times96487}$

= 68.76g

Hence, The mass of Copper electroplated is 68.76 g

Learn more about electroplating:

brainly.com/question/22104403

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1 year ago

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What is the h oh ph and poh of a 0.005m solution of calcium hydroxide?

fiasKO [112]

Answer: $[OH^{-}]= 0.01M or 1.0\times 10^{-2}M$

$[H^{+}]= 1.0\times 10^{-12}M$

pH = 12

pOH = 2

Explanation: Calcium hydroxide ( $Ca(OH)_{2}$ ) is a strong base that dissociates completely.

Dissociation equation of Calcium hydroxide is :

$Ca(OH)_{2} \rightarrow Ca^{+2} + 2OH^{-}$

1. Concentration of [OH-]

1 mol $Ca(OH)_{2}$ produces 2 mol OH- ions.

The given solution is 0.005M $Ca(OH)_{2}$ , then concentration of OH- would be twice the concentration of $Ca(OH)_{2}$

$[OH^{-}] = 0.005\times 2$ = 0.01M or $1.0\times 10^{-2}M$

2.Concentration of [H+]

Concentration of [H+] can be calculated by the formula: $[H^{+}] = \frac{Kw}{[OH^{-}]}$

kw = ionic product of water and its values is $(1\times 10^{-14})$

[OH-] = 0.01 M or $1.0\times 10^{-2}M$

$[H^{+}] = \frac{(1\times 10^{-14})}{[OH^{-}]}$

$[H^{+}] = \frac{(1\times 10^{-14})}{[0.01]}$

$[H^{+}] = 1.0\times 10^{-12}M$

3. pH value

pH is calculated by the formula : $pH = -log[H^{+}]$

$pH = -log[1.0\times 10^{-12}]$

pH = 12

4. pOH value

pOH is calculated by the formula : pOH = 14 - pH

pOH = 14 - 12

pOH = 2

pOH can also be calculated by using a different formula which is :

$pOH = -log(OH^{-})$

$pOH = -log(0.01)$

pOH = 2.

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3 years ago

Which of the following leads to a higher rate of effusion?

Sunny_sXe [5.5K]

Answer:

Lower molar mass :)

Explanation:

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Which diagram shows a pair of electrons that have opposite spins?<br> OT<br> 11<br> 11<br> 个个

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Answer:

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Hellllllllllppppppppppppppp!

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