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ludmilkaskok [199]
3 years ago
10

Two 6.0 kg masses are separated by a distance of 4.0 m. What is the magnitude of the gravitational force between the two masses?

Physics
1 answer:
gogolik [260]3 years ago
5 0

Answer: 1.50075*10^{-10}\ N

Explanation:

For this exercise we need to use the Gravitational Force Formula. This is:

F_g=G(\frac{m_1*m_2}{r^2})

Where F_g is the gravitational force between two objects, G is the gravitational constant (G=6.67*10^{-11}\ \frac{Nm^2}{kg^2}) and r is the distance between the objects.

We know that:

m_1=6.0\ kg\\\\m_2=6.0\ kg\\\\r=4.0\ m

Therefore, in order to calculate the magnitude of the gravitational force between the two masses, we must substitute these values into the formula.

Then we get:

F_g=(G=6.67*10^{-11}\ \frac{Nm^2}{kg^2})(\frac{(6.0\ kg)(6.0\ kg)}{(4.0\ m)^2})\\\\F_g=1.50075*10^{-10}\ N

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a)  V_f = 25.514 m/s

b)  Q =53.46 degrees CCW from + x-axis

Explanation:

Given:

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- Acceleration a = 0.31 i m/s^2

- Time duration for acceleration t = 49.0 s

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(a) What is the magnitude of the satellite's velocity when the thruster turns off?

(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.

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                                   V_f = V_i + a*t

                                   V_f = 20.5 j + 0.31 i *49

                                   V_f = 20.5 j + 15.19 i

- The magnitude of the velocity vector is given by:

                                   V_f = sqrt ( 20.5^2 + 15.19^2)

                                   V_f = sqrt(650.9861)

                                  V_f = 25.514 m/s

- The direction of the velocity vector can be computed by using x and y components of velocity found above:

                                 tan(Q) = (V_y / V_x)

                                 Q = arctan (20.5 / 15.19)

                                 Q =53.46 degrees

- The velocity vector is at angle @ 53.46 degrees CCW from the positive x-axis.

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Answer:

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By solvng equation (1) and (4), we get

R = 9.85 ohm , r = 0.85 ohm

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