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ludmilkaskok [199]
3 years ago
10

Two 6.0 kg masses are separated by a distance of 4.0 m. What is the magnitude of the gravitational force between the two masses?

Physics
1 answer:
gogolik [260]3 years ago
5 0

Answer: 1.50075*10^{-10}\ N

Explanation:

For this exercise we need to use the Gravitational Force Formula. This is:

F_g=G(\frac{m_1*m_2}{r^2})

Where F_g is the gravitational force between two objects, G is the gravitational constant (G=6.67*10^{-11}\ \frac{Nm^2}{kg^2}) and r is the distance between the objects.

We know that:

m_1=6.0\ kg\\\\m_2=6.0\ kg\\\\r=4.0\ m

Therefore, in order to calculate the magnitude of the gravitational force between the two masses, we must substitute these values into the formula.

Then we get:

F_g=(G=6.67*10^{-11}\ \frac{Nm^2}{kg^2})(\frac{(6.0\ kg)(6.0\ kg)}{(4.0\ m)^2})\\\\F_g=1.50075*10^{-10}\ N

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400 N of load can be overcome by an effort of 50 N by using a lever. Calculate the mechanical advantage of the lever.
mars1129 [50]

Answer:

load (l)=400N

Effort(E)=50N

mechanical advantage (MA)= load ÷Effort

(ma)=400÷50

(ma)=8

Explanation:

I copy pasted from the answer from the same question. Remember to first check if ur question is there

4 0
3 years ago
) An ideal Carnot engine extracts 529 J of heat from a high-temperature reservoir during each cycle, and rejects of heat to a lo
enot [183]

Answer:

0.5747 or 57.4%

Explanation:

Your question is not complete so i will assume the right question goes thus;

A Carnot engine extracts 529 J of heat from a high-temperature reservoir during each cycle, and rejects 225 J of heat to a low-temperature reservoir during  the same cycle.  What is the efficiency of the engine?

Efficiency of a Carnot engine is given by [(Th-Tc) / Th]

using the formula above, the resulting equation will give us; (529-225)/529

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3 0
3 years ago
If you drag a sled on the ground, what does the sled experience?
Ilya [14]
The sled experiences friction against the ground
3 0
3 years ago
A soccer ball is kicked from the ground with an initial speed of 19.3 m/s at an upward angle of 45°. a player 54.7 m away in the
dalvyx [7]

Hello there

the answer is

Let the initial position from where the ball is kickedat angle 45 deg, be A. The Horizontal range of the ball (AC) is V2 Sin2θ / g = 38.76 Meters

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3 0
3 years ago
Suppose that a pane of crown glass, with a refractive index of 1.52, is immersed in water, which has a refractive index of 1.33.
mylen [45]

Answer:

the angle made by this ray with normal will be 45°

Explanation:

given,                                                      

refractive index of crown glass = 1.52

refractive index of the water = 1.33        

ray of light in water strikes glass at 45°                      

angle subtended by the light when it reenter water = ?                  

When light enter in the glass from the water it get bend toward normal because refractive index of glass is more than water.              

And when ray comes out of the glass it is parallel to the initial light ray.

hence, the angle made by this ray with normal will be 45°

3 0
3 years ago
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