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almond37 [142]
3 years ago
11

When determining a region's climate, the two main variables considered are the average what? ( They don't have the subject "Scie

nce" here. )
Physics
1 answer:
shutvik [7]3 years ago
3 0
Temperature and precipitation. (They should put a science button in) :-)
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Suppose one night the radius of the earth doubled but its mass stayed the same. What would be an approximate new value for the f
Alex17521 [72]

Answer:

g' = g/4

Explanation:

  • The value of the free-fall acceleration at the surface of the earth, can be obtained applying Newton's 2nd law, assuming that the only force acting on an object at the surface of the earth, is the one produced by the mass of the Earth, i.e. gravity.
  • This force can be expressed according  the Newton's Universal Law of Gravitation , as follows:

       F_{g} = G*\frac{m_{x} *m_{E} }{r_{E}^{2} }  (1)

  • From Newton's 2nd Law, we have:
  • F = m* a (2)
  • Since the left sides in (1) and (2) are equal each other, both right sides must be equal each other also.
  • Simplifying the mass m, we can write the acceleration a in (2) as the acceleration due to gravity, g, as follows:

       g = G*\frac{m_{E} }{r_{E}^{2} }  (3)

  • Since G is an universal constant, and the mass mE remains constant, if we double the radius of  the Earth, the new value for the acceleration due to gravity (let's call it g'), is as follows:

        g' = G*\frac{m_{E} }{(2r_{E})^{2} } =G*\frac{m_{E} }{4*r_{E}^{2} }  = g*\frac{1}{4}  =\frac{g}{4} (4)

4 0
3 years ago
Find the area under the standard normal curve between z=0.19 and z=2.18. round your answer to four decimal places, if necessary.
LiRa [457]

The area under the standard normal curve between z=0.19 and z=2.18 is,

P(0.19<z<2.18)= 0.4101

<h3>How can we calculate the area under the curve?</h3>

To calculate the The area under the standard normal curve  between z=0.19 and z=2.18, we are using two things,

<u>Step 1</u>: The formula,

P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)

<u>Step 2</u>: The statistical values of the area under the curve we get from the picture.

Now we put the known values from the picture in the above formula, we get,

P(0.19<z<2.18)= P(Z<2.18)- P(Z<0.19)

Or, P(0.19<z<2.18)=  0.9854-0.5753

Or, P(0.19<z<2.18)=  0.4101

From the above calculation we can easily conclude that,

The area under the standard normal curve between z=0.19 and z=2.18 is,

P(0.19<z<2.18)= 0.4101

Learn more about the standard normal curve:

brainly.com/question/17088387

#SPJ4

5 0
2 years ago
An object moves in a circular path at a constant speed. what is the direction of the net force acting on the object?
mr Goodwill [35]
In a circular motion im pretty sure
6 0
4 years ago
Please show all the steps and work. The answer is -3.9 m/s2
konstantin123 [22]

Given that,

Initial velocity of the airplane = 66 m/s

Distance = 560 m

Final velocity of the airplane = 0 (stops)

To find,

Acceleration of the airplane.

Solution,

Let us consider that a is the acceleration of the airplane. We can find it using third equation of motion as follows :

v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{0^2-66^2}{2(560)}\\\\a=-3.9\ m/s^2

Therefore, the acceleration of the airplane is -3.9\ m/s^2

8 0
3 years ago
Does this graph represent an endothermic or an exothermic reaction
MaRussiya [10]

Answer:

the graph represents an endothermic reaction

Explanation:

remember:

endo- inside

exo- out

3 0
3 years ago
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