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Salsk061 [2.6K]
3 years ago
13

Suppose that a pane of crown glass, with a refractive index of 1.52, is immersed in water, which has a refractive index of 1.33.

A ray of light traveling in the water strikes the glass at 45° relative to the normal and travels through the pane. What angle, relative to the normal, will the ray of light subtend when it leaves the pane and reenters the water?
Physics
1 answer:
mylen [45]3 years ago
3 0

Answer:

the angle made by this ray with normal will be 45°

Explanation:

given,                                                      

refractive index of crown glass = 1.52

refractive index of the water = 1.33        

ray of light in water strikes glass at 45°                      

angle subtended by the light when it reenter water = ?                  

When light enter in the glass from the water it get bend toward normal because refractive index of glass is more than water.              

And when ray comes out of the glass it is parallel to the initial light ray.

hence, the angle made by this ray with normal will be 45°

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-2.0 m/s²

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\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

a

​

 

=

Δt

v

f

​

−v

i

​

​

=

3.5s

−21

s

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​

−(−14

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