To solve this problem we will use the equilibrium conditions in the Electrostatic Forces. In turn, we will use the concept formulated from Coulomb's laws to determine the intensity of the Forces and make the respective considerations.

Our values for the two charges are:

$q_1 = -Q_0$

$q_2 = -4Q_0$

As a general consideration we will start by determining that they are at a unit distance (1) separated from each other. And considering that both are negative charges, they will be subjected to repulsive force. Said equilibrium compensation will be achieved only by placing a third force between the two.

Let the third charge be $q_3 = +Q$ is placed at a distance x from $q_1$

$F_{1,3} = \frac{k(-Q_0)(+Q)}{x^2}$

The force on $q_3$ due to $q_2$ is

$F_{2,3} = \frac{k(-4Q_0)(+Q)}{1-x^2}$

The condition of equilibrium is

$F_{1,3} = F_{2,3}$

$\frac{k(-Q_0)(+Q)}{x^2}= \frac{k(-4Q_0)(+Q)}{1-x^2}$

$\frac{1}{x^2} = \frac{4}{(1-x)^2}$

$x = 0.331$ from $q_1$

To find the magnitude of $q_3$ we use $F_{1,2} = F_{1,3}$

$\frac{k(-Q_0)(4Q_0)}{1^2}= \frac{k(-Q_0)(Q)}{0.331^2}$

$Q = 0.43Q_0$

The magnitude of the third charge must be 0.43 the first charge $Q_0$

3 0

4 years ago

If a photon has a frequency of 5.20 × 1014 hertz, what is the energy of the photon? Given: Planck's constant is 6.63 × 10-34 jou

Virty [35]

Answer:
E=h.f

=5.2×1014×6.63×10^-34

E=3.496×10^-30 J

4 0

3 years ago

What factor affects sensation

Gnesinka [82]

Answer:

D physiological condition

Explanation:

Sensation and perceptions are complimentary to each other but have different roles within the brain. Sensations are the process of experiencing the world with the five senses and sending that information to the brain. Perceptions are the way we interpret sensations.

8 0

3 years ago

A cyclical motion occurs because of density differences in the mantle. Heated, less dense lower regions of the fluid mantle rise

Marta_Voda [28]

The answer for this is B

3 0

3 years ago