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2 years ago

8

Topic: Room Preparation Select one physician assisted examination or procedure, can be routine or surgical. Create a checklist o

f the items the procedure will require. Be sure to include equipment and disposable inventory.

1 answer:

kvasek [131]2 years ago

8 0

I don't know the answer. Can I ask your help to answer that question? pls.

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What is the molar ratio for the following equation after it has been properly balanced?

slava [35]

The answer
<span>the molar ratio for the following equation
____C3H8 + ____O2 Imported Asset ____CO2 + ____ H2O

</span>after it has been properly balanced:
__1_C3H8 + ____5O2 Imported Asset ____3CO2 + ____ 4H2O

proof:
number of C =3 (C3H8; 3CO2)
number of H =8 (C3H8 ; 4H2O)
number of O = 10(5x2) or (2x3+4) (5O2;4H2O)

the answer is
<span>Reactants: C3H8 = 1, O2 = 8; Products: CO2 = 3 and H2O = 4</span>

4 0

2 years ago

Which mixture can be separated based on differences in the particle size of the components?

Rina8888 [55]

Answer: Mixtures you can separate are like cereal and milk. Hope that helps

Explanation: Filteration is required to separate a mixture.

So heterogeneous mixures (that contain substances with different particle sizes) can be separated with a filter.

Homogeneous mixtures are uniform in composition so they will not be able to be separated.

5 0

2 years ago

For the reaction C2H4(g) + H2O(g) --> CH3CH2OH(g)

Dominik [7]

Answer : The value of equilibrium constant for this reaction at 262.0 K is $3.35\times 10^{2}$

Explanation :

As we know that,

$\Delta G^o=\Delta H^o-T\Delta S^o$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

$\Delta H^o$ = standard enthalpy = -45.6 kJ = -45600 J

$\Delta S^o$ = standard entropy = -125.7 J/K

T = temperature of reaction = 262.0 K

Now put all the given values in the above formula, we get:

$\Delta G^o=(-45600J)-(262.0K\times -125.7J/K)$

$\Delta G^o=-12666.6J=-12.7kJ$

The relation between the equilibrium constant and standard Gibbs free energy is:

$\Delta G^o=-RT\times \ln k$

where,

$\Delta G^o$ = standard Gibbs free energy = -12666.6 J

R = gas constant = 8.314 J/K.mol

T = temperature = 262.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

$-12666.6J=-(8.314J/K.mol)\times (262.0K)\times \ln k$

$k=3.35\times 10^{2}$

Therefore, the value of equilibrium constant for this reaction at 262.0 K is $3.35\times 10^{2}$

3 0

2 years ago

Suppose a student did not fully redissolve the Al(OH)3 that initially formed upon the addition of H2SO4. Predict and explain how

kirza4 [7]

<span>Percent yield is the measured recovery of a substance in grams divided by the theoretical amount of substance expected in grams (times 100 to convert to %). Undissolved Aluminum trihydroxide would add mass to the Aluminum sulphate one is making here. The measured mass would be inaccurately high, increasing the percent yield calculated.</span>

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2 years ago

Glaciers are agents of deposition and erosion. When we talk about glacial erosion, we consider both the erosion processes and th

const2013 [10]

I think it is B

Explained answer:
Glaciers dissolve and melt because they are made out of ice

7 0

2 years ago