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3 years ago

Help quick physics area question

Physics

1 answer:

zlopas [31]3 years ago

8 0

Answer: The area of brick in contact with the floor is 1539 $cm^{3}$ .

Explanation:

Given: Length = 19 cm

Width = 9 cm

Height = 9 cm

As the brick is rectangular in shape. Hence, its area will be calculated as follows.

$Area = length \times width \times height$

Substitute the values into above formula as follows.

$Area = length \times width \times height\\= 19 cm \times 9 cm \times 9 cm\\= 1539 cm^{3}$

Thus, we can conclude that area of brick in contact with the floor is 1539 $cm^{3}$ .

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A river flows with a speed of 0.600 m/s. A student first swims upriver 0.500 km, then turns around and returns to his starting p

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a) 1111.0 seconds

b) 833.3 s

c) Because of proportions

Explanation:

a) Total time of round trip is the sum of time upriver and time downriver

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Time upriver is calculated with the net speed of student and 0.500 km:

$t_{up}=\frac{d_{istance}}{|v_{swimmer}|} ;\\v_{swimmer}=v_{relative to river}+v_{river}=-1.2+0.6=-0.6 m/s\\t_{up}=\frac{500 m}{0.6 m/s}=833.3 s$

(Becareful with units 0.5 km= 500m) Similarly of downriver:

$t_{down}=\frac{d_{istance}}{|v_{swimmer}|} ;\\v_{swimmer}=1.2+0.6=1.8 m/s\\t_{down}=\frac{500 m}{1.8 m/s}=277.7 s$

So the sum is:

$t_{total}=1111.0s$

b) Still water does not affect student speed, so total time would be simply:

$t_{total}=\frac{1000 m}{1.2 m/s}=833.3 s$

c) For the upriver trip, student moved half the distance in half speed of the calculation in b), so it kept the same ratio and therefore, same time. So the aditional time is actually the downriver.

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3 years ago