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Liono4ka [1.6K]
3 years ago
7

Help quick physics area question

Physics
1 answer:
zlopas [31]3 years ago
8 0

Answer: The area of brick in contact with the floor is 1539 cm^{3}.

Explanation:

Given: Length = 19 cm

Width = 9 cm

Height = 9 cm

As the brick is rectangular in shape. Hence, its area will be calculated as follows.

Area = length \times width  \times height

Substitute the values into above formula as follows.

Area = length \times width  \times height\\= 19 cm \times 9 cm \times 9 cm\\= 1539 cm^{3}

Thus, we can conclude that area of brick in contact with the floor is 1539 cm^{3}.

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Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point,F⃗ 1F→1F_1_vec has a magnitude of 8.80 NN and is directed at an an
castortr0y [4]

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Explanation:

You apparently want the sum of forces ...

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Your angle reference is a bit unconventional, so we'll compute the components of the forces as ...

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This way, the 2nd quadrant angle that has a negative angle measure will have a positive y component.

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The resultant component forces are ...

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Then the magnitude and direction of the resultant are

  F∠γ = (√(9.15309² +1.71982²))∠arctan(-1.71982/9.15309)

  F∠γ ≈ 9.31∠-10.6°

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