For this problem, we use the derived equations for rectilinear motion at constant acceleration. The equations used for this problem are:
a = (v - v₀)/t
2ax = v² - v₀²
where
a is the acceleration
x is the distance
v is the final velocity
v₀ is the initial velocity
t is the time
The solution is as follows;
a = (60mph - 30 mph)/(3 s * 1 h/3600 s)
a = 36,000 mph²
2(36,000 mph²)(x) = 60² - 30²
Solving for x,
x = 0.0375 miles
The answer is D. Isotopes.
Hope that helped.
I belive it would power I’m not 100% sure. If it’s not power then force
The distance covered is 25.9 m.
<h3>How deep is the cave?</h3>
We know that the speed of sound refers to the speed with which an sound moves in an object.
Given that;
speed of sound = 345m/s
Time taken = 0.15s
We know that;
v = 2d/t
v = speed of sound
d = distance
t = time taken
vt = 2d
d = vt/2
d = 345m/s * 0.15s/2
d = 25.9 m
Learn more about speed of sound:brainly.com/question/15137350
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Initial velocity of a car is 36 km/h . Find the distance after min, if it goes with acceleration 2 m/s².
Initial velocity, u = 36 km/h
Time, t = 1min
Acceleration, a = 2m/s²
Apply 2nd equation of motion
