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kolbaska11 [484]
2 years ago
15

A 2.40 μC charge is subject to a 3.00 mN force due to an Electric Field. What is the magnitude of the Electric Field at the loca

tion of the charge?
Physics
1 answer:
Bezzdna [24]2 years ago
4 0
<h2>Electric field at the location of the charge is 1250 N/C</h2>

Explanation:

Electric field is the ratio of force and charge.

Force, F = 3.00 mN = 3 x 10⁻³ N

Charge, q = 2.40 μC = 2.40 x 10⁻⁶ C

We have

                 E=\frac{F}{q}\\\\E=\frac{3\times 10^{-3}}{2.40\times 10^{-6}}\\\\E=1250N/C

Electric field at the location of the charge is 1250 N/C

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