All categories

3 years ago

What are four minerals that are commonly taken from ores

1 answer:

5 0

If it helps or doesn't I'm sorry, but if you even played the game Minecraft just remember it.

Gold, silver, coal, and iron come from ores.

You might be interested in

when you squeeze the rubber bulb of a perfume atomizer how do you change the air pressure at the top of the tube

LuckyWell [14K]

You push air and perfume out of the tube, creating a small vaccum that pulls more perfume into the tube

8 0

4 years ago

A 1,200 kg car rolls down a hill with its brakes off and transmission in neutral. At one moment it is moving 5.0 m/s. A little l

Y_Kistochka [10]

The change in kinetic energy of the car is equivalent to the change in its potential energy. Thus:
K.E = P.E
1/2 x mΔv² = mgΔh
h = (8.2² - 5²) / 2(9.81)
h = 2.15 meters

4 0

4 years ago

Six automobiles are initially traveling at the indicated velocities. The automobiles have different masses and velocities. The d

KIM [24]

Answer:

a)Car E = Car D > (Car F = Car B = Car C) > Car A

b)Car E = Car D > (Car F = Car B = Car C) > Car A

Explanation:

Car A: mass = 500 kg; speed = 10 m/s

Car B: mass = 2000 kg;speed = 5 m/s

Car C:mass = 500 kg; speed = 20 m/s

Car D: mass = 1000 kg; speed = 20 m/s

Car E:mass = 4000 kg; speed = 5 m/s

Car F: mass = 1000 kg; speed = 10 m/s

Part a) Now we know that momentum of each car is product of mass and velocity , so we will have

$P_1 = m \times v\\P_1 = (500)(10)\\P_1 = 5 \times 10^3 kg m/s$

<em>Car B:</em>

$P_2 = m v\\P_2 = (2000)(5)\\P_2 = 10^4 kg m/s$

Car C:

$P_3 = m v\\P_3 = (500)(20)\\P_3 = 10^4 kg m/s$

Car D:

$P_4 = m v\\P_4 = (1000)(20)\\P_4 = 2\times 10^4 kg m/s$

Car E:

$P_5 = m v\\P_5 = (4000)(5)\\P_5 = 2\times 10^4 kg m/s$

Car F:

$P_6 = m v\\P_6 = (1000)(10)\\P_6 = 10^4 kg m/s$

So the momentum is given as ,

Car E = Car D > (Car F = Car B = Car C) > Car A

Part b)Impulse is given as change in momentum so here we can say that final momentum of all the cars will be zero as they all stops and hence the impulse is same as initial momentum of the car

so the order of impulse from largest to least is given as

Car E = Car D > (Car F = Car B = Car C) > Car A

3 0

3 years ago

A coil consists of 180 turns of wire. Each turn is a square of side d=30 cm, and a uniform magnetic field directed perpendicular

alexira [117]

Answer:

Emf induced i equal to 329.4 volt

Explanation:

Note : Here i think we have to find emf induced in the coil

Number of turns in the coil N= 180

Sides of square d = 30 cm = 0.3 m

So area of the square $A=0.3\times 0.3=0.09m^2$

Magnetic field is changes from 0 to 1.22 T

Therefore $dB=1.22-0=1.22T$

Time interval in changing the magnetic field dt = 0.06 sec

Induced emf is given by

$e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}$

$e=-180\times 0.09\times \frac{1.22}{0.06}=329.4volt$

8 0

4 years ago

A 11 547,83-N car is raised using a hydraulic lift, which

kati45 [8]

Answer:

75457.54816 N

Explanation:

$F_1$ = Initial force

$F_2$ = Weight of car = 11547.83 N

$r_1$ = Smaller radius = 5 cm

$r_2$ = Larger radius = 19.56 cm

From Pascal's law we have

$\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow F_1=F_2\dfrac{A_1}{A_2}\\\Rightarrow F_1=11547.83\dfrac{\pi r_1^2}{\pi r_2^2}\\\Rightarrow F_1=11547.83\dfrac{5^2}{19.56^2}\\\Rightarrow F_1=754.57548\ N$

The force is 754.57548 N

3 0

4 years ago