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Bogdan [553]
3 years ago
10

a mass stands on a platform which vibrates simple harmonically in a vertical Direction and with a frequency of 5 Hertz. show tha

t the mass loses contact with the platform when the displacement exceeds 10^-2.
Physics
1 answer:
Nastasia [14]3 years ago
4 0

shm

displacement is A*sin 2pi f t

vel =( A*2*pi*f*)*cos 2 pi f t

accn =-( A*2*pi*f*)^2*sin 2 pi f t

accn = (0.01*2*3*5)

accn = (0.01x30)^2=9


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I) Give two practical<br>application of static friction<br>​
bulgar [2K]

1).  Walking / Driving

If there were no static friction between the soles of your shoes and the ground, then you could move your feet back and forth but your body would never go anywhere.

Same for using tires to move a car, a bus, a bicycle or a motorcycle.

2).  Sleeping

If there were no static friction between your jammies and the sheet, you would slide right off of the bed whenever there was the slightest breeze of air in the room.  

7 0
3 years ago
A wave has a frequency of 775 Hz. What is its period?
Leto [7]

The period is simply the inverse of the frequency, therefore:

T = 1 / f

T = 1 / 775 Hz

T = 0.001290 s    → possible answer

T = 1.29 × 10⁻³ s   → possible answer

T = 1.29 ms          → possible answer

4 0
3 years ago
A flywheel with radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.400 rad/s2.For a po
oksian1 [2.3K]

Answer:

0.12\ m/s^2

Explanation:

Given that,

The radius of a flywheel, r = 0.3 m

Angular acceleration of a flywheel, \alpha =0.4\ rad/s^2

We need to find the magnitude of the tangential acceleration after 2.00 s of acceleration.

The relation between the tangential and angular acceleration is given by :

a_t=r\alpha \\\\a_t=0.3\times 0.4\\\\a_t=0.12\ m/s^2

So, the required magnitude of tangential acceleration is 0.12\ m/s^2.

6 0
3 years ago
Calculate the magnitude of the gravitational force between Goku with a mass of 62 kg and King Kai’s planet with a mass of 1.458x
Brilliant_brown [7]

Answer:

6227.866 N

Explanation:

F = G . m(goku) . m(planet) / d²

F = 6.674 x 10-¹¹ x 62 x 1.458 . 10¹⁵ / 31²

F = 6227.866 N

7 0
3 years ago
A 4.00-kg particle moves along the x axis. Its position varies with time according to x 5 t 1 2.0t 3, where x is in meters and t
White raven [17]

Answer:

Explanation:

Given equation is ,

x =t + 2 t³ ,

dx/dt = velocity ( v ) = 1 + 6 t²

a) kinetic energy = 1/2 m v² = .5 x 4 ( 1 + 6 t² )² = 2 ( 1 + 6 t²)²

b ) Acceleration = dv /dt = 12 t .

force( F ) = mass x acceleration = 4 x 12 t = 48 t

Power = force x velocity = 48 t x ( 1 + 6 t²). = 48 t + 288 t³ )

work done = ∫ F dx =∫ 48 t x( 1 + 6t² )dt ; =  [48t²/2 + 48 x 6 x t³ /3 = 24 t² + 96 t³ )]₀² =  864 J

6 0
3 years ago
Read 2 more answers
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