Answer: 4.4 cm.
Explanation:
Rise of water in the smaller tube= h1=8.8 centimeter(cm)
Radius of the smaller tube= r
Rise of water in the larger tube= h2 (in centimeter).
The radius of the larger tube is twice that of the smaller tube means that;
The radius in the larger tube is 2r ( 2 multiply by the radius r, of the smaller tube)
Using Jurin's law;
height or rise of liquid is inversely proportional to its radius, r.
That is; hr= constant.
Therefore, we have;
h1 × r1 = h2 × r2.
Rise in smaller tube × radius of the smaller tube = height of the larger tube × radius of the larger tube.
8.8 cm × r = h2 × 2r
= (8.8cm)r = (h2) 2r
Divide both sides by 2r, we then have;
8.8cm r/ 2r = h2
h2= 4.4cm
Therefore, the height or rise in large tube is half of that of the smaller tube.
Answer: The formula of Newtons second law of motion is F=MA so therefore it would be written like this Force = Mass X Acceleration
F = 5 x 2
F = 10 N
Answer:
0.00493 m/s
Explanation:
T = Temperature of the isotope = 85 nK
R = Gas constant = 8.341 J/mol K
M = Molar mass of isotope = 86.91 g/mol
Root Mean Square speed is given by
The Root Mean Square speed is 0.00493 m/s
Answer:
4.37 * 10^-4 J
Explanation:
Energy stored :
mgΔl / 2
m = mass = 10kg ; g = 9.8m/s² ; r = cross sectional Radius = 1cm = 1 * 10-2 m
Δl = mgl / πr²Y
Y = Youngs modulus = Y=3.5 ×10^10 ; l = Length = 1m
Δl = (10 * 9.8 * 1) / π * (1 * 10^-2)²* 3.5 ×10^10
Δl = 98 / 3.5 * π * 10^6
Δl = 0.00000891267
Energy stored :
mgΔl / 2
(10 * 9.8 * 0.00000891267) / 2
= 0.00043672083 J
4.37 * 10^-4 J
