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sineoko [7]
3 years ago
7

A high-diver of mass 59.8 kg jumps off a board 10.0 m above the water. If, 1.00 s after entering the water his downward motion i

s stopped, what average upward force did the water exert?
a. 108 N.
b. 4.27 N.
c. 840 N.
d. 598 N.
e. None of the other answers is correct.
Physics
1 answer:
irinina [24]3 years ago
6 0

la respuesta correcta es la "E"

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A student pushes on a crate with a force of 100 N directed to the right. What force does the crate exert on the student?
sattari [20]

Answer:

The Force exerted on the student by crate will be 100 N.

Explanation:

As per the given Question student is trying to push the crate in right direction with the force of 100N.

And we know that, Newton's third law states that every action has equal and opposite reaction.

So from the Newton's 3rd law of motion it is very clear the student must be experiencing the same amount of force which he is applying.

6 0
3 years ago
What is 25 degrees Celsius equal to in Fahrenheit? I need to know how to do it to, so give me a formula, and it would help if yo
andreev551 [17]
C= 5/9*(F - 32) so F=C*9/5 + 32

F= 25*9/5 +32 = 77 Fahrenheit
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3 years ago
Which charateristic of the observant function?
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Answer:

All people with the observant trait are often a steadying force that always wants to get things done. Their energy is very elegant in the sense of working on real things in real time.

Explanation:

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8 0
2 years ago
Convert 1215 m to km.<br> Answer:
IgorC [24]

Answer:

it is 12.15 km

Explanation:

1215 km ÷1000

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8 0
3 years ago
The radioactive element strontium-90 has a half-life of 28 years. Suppose we start with a 50-g mass of strontium-90. How much wi
kramer

Answer: 7.71 grams

Explanation:

Half-life of strontium-90 = 28 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{28\text{years}}

k=0.02475\text{years}^{-1}

Now we have to calculate the age of the sample:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 0.02475\text{years}^{-1}

t = age of sample  = 174 years

a = initial amount of the reactant  = 50 g

a - x = amount left after decay process  = ?

Now put all the given values in above equation, we get

174=\frac{2.303}{0.02475}\log\frac{50}{a-x}

(a-x)=7.71g

Thus amount left after 174 years is 7.71 grams.

7 0
3 years ago
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