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-BARSIC- [3]
3 years ago
5

Calculate the energy that 1.5 kg of mass contains

Physics
1 answer:
Vsevolod [243]3 years ago
4 0

Answer:

4.5(10)^8 joules

Explanation:

Mass–energy equivalence is the principle that says that anything that has mass has an equivalent amount of energy. Converse is also true.

The relation between energy and mass is given by E=mc^2

Here, E denotes energy, m denotes mass and c denotes speed of light

Mass (m)=1.5\,\,kg

Speed of light (c) = 3 × 10^8 m/s

Therefore,

E=1.5(3)(10)^8=4.5(10)^8  joules.

The S.I. unit of energy is joules which is equal to 1\,\,kg\,\,m^2/s^2

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2. Air at a temperature of 20 ºC passes through a pipe with a constant velocity of 40 m/s. The pipe goes through a heat exchange
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Answer:

a) Q = 1436 kW

b) P ≈ 776 kW

Explanation:

Let's begin by listing out the given parameters:

T1 = 20 °C, u = 40 m/s, T2 = 820 °C, P = 4.3 kW, m = 2.5 kg/s, T3 = 510 °C, V1 = 40 m/s,

V2 = 40 m/s, V3 = 55 m/s, ṁ = 2.5 kg/s

To solve the question, we make this assumption that the size of the pipe is constant

a) No change in velocity implies that heat added is isochoric

Q = m * C * ΔT

Cv of air at 300 K(≈20 °C) = 0.718

Q = 2.5 * 0.718 * (820 − 20)

Q = 1436 kW

b) P = ṁ * Cp * ΔT + ṁ * (V2² - V3²) ÷ 2000] - Ql

V2² - V3² = 55² - 40² = 1425

ΔT = T2 - T3 = 820 - 510 = 310 °C

Cp of air at 300 K(≠20 °C) = 1.005 kJ/kgK

Ql = 4.3 kW

P = 2.5 * (1.005 * 310) + 2.5 * (1425 ÷ 2000) - 4.3

P = 778.875 + 1.78125 - 4.3 = 776.35625

P ≈ 776 kW

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