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Anvisha [2.4K]
3 years ago
8

Which type of energy conversion takes place when a lightbulb is turned on?

Physics
1 answer:
Vlad1618 [11]3 years ago
8 0
Thermal potential energy is converted into electric energy.
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How much positive electric charge is in 10 moles of carbon? NA=6.022×1023mol−1, e=1.60×10−19C.
levacccp [35]

Answer:

4.75 x 10^-25 kg

Explanation:

5 0
3 years ago
50 points!!! Kinetics
iris [78.8K]

Answer:

98 m √

Explanation:

How about s = Vo * t + ½at² ?

s = h = Vo * 2s - 4.9m/s² * (2s)² = 2Vo - 19.6

and

h = Vo * 10s - 4.9m/s² * (10s)² = 10Vo - 490

Subtract 2nd from first:

0 = -8Vo + 470.4

Vo = 58.8 m/s

h = 58.8m/s * 2s - 4.9m/s² * (2s)² = 98 m

3 0
3 years ago
Read 2 more answers
Define limitations in the operation conditions of a pn junction<br>​
suter [353]

Answer:

Such limitations are given below.

Explanation:

  • Each pn junction provides limited measurements of maximum forwarding current, highest possible inversion voltage as well as the maximum output level.
  • If controlled within certain adsorption conditions, the pn junction could very well offer satisfying performance.
  • In connector operation, the maximum inversion voltage seems to be of significant importance.

6 0
3 years ago
If a 20 g cannonball is shot from a 5 kg cannon with a velocity of 100
balu736 [363]

Strange as it may seem, the statement in the question appears to be <em>TRUE</em>.  

-- Before the shot, neither the cannon nor the ball is moving, so their combined momentum is zero.  

-- Since momentum is conserved, we know immediately that their combined momentum AFTER the shot also has to be zero.

-- (20g is rather puny for a "cannonball" ... about the same weight as four nickels. But we'll take your word for it and just do the Math and the Physics.)

-- Momentum = (mass) x (velocity)

After the shot, the momentum of the cannonball is

(0.02 kg) x (100 m/s ==> that way)

Momentum of the ball = 2 kg-m/s ==> that way.

-- In order for both of them to add up to zero, the momentum of the cannon must be (2 kg-m/s this way <==) .

Momentum of cannon = (5 kg) x (V m/s this way <==)

2 kg-m/s this way <== = (5 kg) x (V m/s this way <==)

Divide each side by (5 kg):

V m/s  =  (2/5) m/s this way <==

Speed of recoil of the cannon = <em>-- 0.4 m/s</em>

3 0
3 years ago
How much displacement will a spring with a constant of 120N / m achieve if it is stretched by a force of 60N?
Andrew [12]

Answer:

Explanation:

There's a formula for this:

F = k*displacement

F being force, k being the spring constant, and displacement being the change in x

We are given the force and the spring constant, so this is essentially isolating the Δx term. Do 60N/120N per meter. The newtons cancel out and you get a final answer of Δx = 0.5 meters

3 0
3 years ago
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